Two circles<span> of </span>radius<span> 4 are </span>tangent<span> to the </span>graph<span> of y^</span>2<span> = </span>4x<span> at the </span>point<span> (</span>1<span>, </span>2<span>). ... I know how to </span>find<span> the </span>tangent<span> line from a circle and a given </span>point<span>, but ... </span>2a2=42. a2=8. a=±2√2. Then1−xc=±2√2<span> and </span>2−yc=±2√2. ... 4 from (1,2<span>), so you could </span>find these<span> centers, and from there the</span>equations<span> of the circle
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The answer is b. The Remainder<span> Theorem says that if a polynomial </span>f(x<span>) is divided by </span>x<span> – k, then </span>the remainder<span> is </span>f(k). k=3 in our case, so the remainder is simply f(3). Plug in x=3 into <span>f(x) = 7x4 + 12x3 + 6x2 - 5x + 16. f(x)=946. So the answer is b.</span>
36.91 is the answer 67.1x.55
Answer:
36
Step-by-step explanation:
Area of a triangle = (bh)/2
Where b = base length and h = height
Given base length: 18ft
Given height: 4ft
This being known let's define the variables
b = 18
h = 4
Now to find the area we simply plug in these values into the formula
Area = (18)(4)/2
Simplify multiplication 18 * 4 = 72
Area = 72/2
Simplify division
Area = 36
