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Bess [88]
3 years ago
12

N a school trip, students stopped for breakfast. They chose between a bagel and a ham biscuit.

Mathematics
1 answer:
svetlana [45]3 years ago
4 0
<h2><u><em>GLAD YOU FOUND YOUR ANSWER!!!!!!</em></u></h2>

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PLEASE HELP ME!!!!!!!
Sidana [21]
He has come from the hole in the roof because the text states that he did not come from a door, a window, or a chimney, and that is the only answer that was left.
4 0
3 years ago
Consider functions of the form f(x)=a^x for various values of a. In particular, choose a sequence of values of a that converges
sleet_krkn [62]

Answer:

A. As "a"⇒e, the function f(x)=aˣ tends to be its derivative.

Step-by-step explanation:

A. To show the stretched relation between the fact that "a"⇒e and the derivatives of the function, let´s differentiate f(x) without a value for "a" (leaving it as a constant):

f(x)=a^{x}\\ f'(x)=a^xln(a)

The process will help us to understand what is happening, at first we rewrite the function:

f(x)=a^x\\ f(x)=e^{ln(a^x)}\\ f(x)=e^{xln(a)}\\

And then, we use the chain rule to differentiate:

f'(x)=e^{xln(a)}ln(a)\\ f'(x)=a^xln(a)

Notice the only difference between f(x) and its derivative is the new factor ln(a). But we know  that ln(e)=1, this tell us that as "a"⇒e, ln(a)⇒1 (because ln(x) is a continuous function in (0,∞) ) and as a consequence f'(x)⇒f(x).

In the graph that is attached it´s shown that the functions follows this inequality (the segmented lines are the derivatives):

if a<e<b, then aˣln(a) < aˣ < eˣ < bˣ < bˣln(b)  (and below we explain why this happen)

Considering that ln(a) is a growing function and ln(e)=1, we have:

if a<e<b, then ln(a)< 1 <ln(b)

if a<e, then aˣln(a)<aˣ

if e<b, then bˣ<bˣln(b)

And because eˣ is defined to be the same as its derivative, the cases above results in the following

if a<e<b, then aˣ < eˣ < bˣ (because this function is also a growing function as "a" and "b" gets closer to e)

if a<e, then aˣln(a)<aˣ<eˣ ( f'(x)<f(x) )

if e<b, then eˣ<bˣ<bˣln(b) ( f(x)<f'(x) )

but as "a"⇒e, the difference between f(x) and f'(x) begin to decrease until it gets zero (when a=e)

3 0
3 years ago
How do you do this?????
Setler79 [48]
The lowest common multiple of 7 and 5 is 35, so you divide 365 by 35, the whole number is your answer,
the answer is 10
4 0
3 years ago
Tuiton at a certain college recently increased from $4000 to $5000. Find the ratio of the increase in price to the original pric
koban [17]
The increase is $5000-$4000=$1000.  The ratio of this increase to the original price is 

$1000
-------- = 1/4 (no units of measurement here)
$4000
8 0
3 years ago
Solve the following quadratic equation for all value of c i'm simplest form <br> 5(x-2)^2=20
xz_007 [3.2K]

Answer:

x=-2 and x=0

Step-by-step explanation:

5(x-2)^2 =  20; divide by 5 both sides

(x-2)^2 = 4; take the square root of both sides

(x-2) = ±2, now set it equal to positive 2 and negative 2

x-2 = 2

x=4

AND

x-2 = -2

x=0

8 0
3 years ago
Read 2 more answers
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