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wlad13 [49]
3 years ago
7

An object has a mass of 4kg and an average acceleration of 10m/s/s what is the force​

Physics
1 answer:
Alisiya [41]3 years ago
4 0
Force = mass x acceleration
Force = 4kg x 10m/s^2
Force = 40N
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8.
eimsori [14]
B. Unbalanced force
3 0
3 years ago
How many Sig Figs (Significant Figures) are in each number?<br><br> 5070.0<br><br> 870.064080
nlexa [21]

∑ Hey, Lethality ⊃

Answer:

5070.0 has 5 significant figures

870.064080 has 9 significant figures

Explanation:

<u><em>Given:</em></u>

<em>How many Sig Figs (Significant Figures) are in each number?</em>

<em>5070.0</em>

<em>870.064080</em>

<u><em>Solution:</em></u>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>5070.0</em>

<em>5070.0 has 5 significant figures ( 5 , 0 , 7 , 0 , and 0 )</em>

<em>Number of significant figures: 5</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em>870.064080</em>

<em>870.064080 has 9 significant figures ( 8, 7 ,0,0, 6,4,0,8 and 0 )</em>

<em>Number of significant figures: 9</em>

<em>-------------------------------------------------------------------------------------------------------------</em>

<em />

<u><em>xcookiex12</em></u>

<em>8/23/2022</em>

5 0
1 year ago
Determine the minimum wavelength of light absorbed by (a) diamond, (b) gallium phosphide and (c) tin sulfide if the gap energies
Talja [164]
I would say B.
I hope this helps!
7 0
3 years ago
As the sun sets on the horizon, its rays are ____________ by the ocean water. A) absorbed B) diffracted C) reflected D) refracte
nevsk [136]

C: reflected

because the sun shines on the water when u look into the water u can see the sun

6 0
2 years ago
If a cell phone is dropped from a very tall building, how far has the phone fallen after 2.7 seconds, neglecting air resistance?
Zielflug [23.3K]
The free fall of the phone is an uniformly accelerated motion toward the ground, with constant acceleration equal to
g=9.81 m/s^2

So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by
y(t) =  \frac{1}{2}gt^2
And if we substitute t=2.7 s, we find the distance covered:
y(t)=  \frac{1}{2}(9.81 m/s^2)(2.7 s)^2=35.8 m
6 0
2 years ago
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