It would be a bike that doesn't use an electric circuit.
An important difference between a universal and a split-phase motor is that the split-phase motor has
A. two brushes attached to the stator.
B. a single coil formed on the rotor.
<u>C. two windings on the stator. </u>
D. an armature with a commutator.
Answer:
See below...
Explanation:
Let’s express ⟨α⟩ in terms of ωi , ωf , and Δt. and torque in terms of It , ωi , ωf , and Δt.
STEP 1.
The rate of change of angular velocity is Angular acceleration.
The net change in angular velocity is Average angular acceleration divided by the elapsed time.
⟨α⟩ = ω f −ω i/Δt
STEP 2.
Torque is assumed this way
dω
τ = I ----
dt
.
⟨τ ⟩ = I t (ω f −ω i )/Δt
The Period of the resulting shm will be T=39.7
<u>Explanation:</u>
<u>Given data</u>
m=3kg
d=.06m
k=1200 N/m
Θ=3 °
T=?
we have the formulas,
I = (1/6)Md2
F = ma
F = -kx = -(mω2x)
k = mω2 τ = -d(FgsinΘ)
T=2 x 3.14/ √(m/k)
Solution for the given problem would be,
F=-Kx (where x= dsin Θ)
F=-k dsin Θ
F=-(1200)(.06)sin(3 °)
F=-10.16N
<u>By newton's second law.</u>
F = ma
a= F/m
a=(-10.16N)/3
a=3.38
<u>using the k=mω value</u>
k=mω
ω=k/m
ω=1200/3
ω=400
<u>Using F = -kx value</u>
x = F/-k
x=(-10.16)/1200
x=0.00847m
<u>Restoring the torque value </u>
τ = -dmgsinΘ where( τ = Iα so.).. Iα = -dmgsinΘ α = -(.06)(4)α =
α =(.06)(4)(9.81)sin(4°)
α=-1.781
<u>Rotational to linear form</u>
a = αr
r = .1131 m
a=-1.781 x .1131 m
a=-0.2015233664
<u>Time Period</u>
T=2 x 3.14/ √(m/k)
T=6.28/√(3/1200)
T=6.28/0.158
T=39.7
Answer:
Explanation:
Given
1 ) 140 m west in 45 s .
2 ) 90 m east in 25 s .
a )
distance travelled in first 45 s = 140 m
b ) distance travelled in next 25 s = 90 m
c ) Total distance travelled = 140 m + 90 m
= 230 m
d ) average speed in first 45 s
= distance in 45 s 45
= 140 / 45 = 3.11 m /s
e ) average speed in next 25 s
distance in 25 s / 25
= 90 / 25 = 3.6 m /s
f ) average in entire trip
= total distance / total time
= (140 + 90) / ( 25 + 45 )
= 3.28 m /s
g )
displacement in first 45 s = 140 m towards west
h )
displacement in next 25 s = 90 m towards east
i )
total displacement = 140 - 90
= 50 m towards west .
