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Andreas93 [3]
2 years ago
13

Explain what physicists mean when they say that the de Broglie wavelength relates to the probability distribution wave function.

Physics
1 answer:
Ksju [112]2 years ago
7 0

Answer:

Because it unites particle and wave nature.

Explanation:

De Broglie wavelength can be defined as the,

\lambda =\frac{h}{mv}

Here, h is planks constant, m is the mass of electron, v is the velocity of electron.

Since the de Broglie wavelength can behave like the photon wavelength with respect to the  momentum

It unites particles and waves nature ,so De Broglie wavelengths is probability waves associated with the wave function according to physicists.

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A cube and a square pyramid were joined to form the composite solid. A cube with side lengths of 12 inches. A square pyramid wit
Vesna [10]

Answer:

i think it is the first option.

6 0
3 years ago
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Of the 5000 species of mammals, 250 species are carnivorous. What is the ratio of carnivorous to mammals?
Mekhanik [1.2K]

Answer: The ratio of carnivorous species to all mammal species is 1:20

Explanation:

250:5000 = 250/250 = 1

250:5000 = 5000/250 = 20

Answer = 1:20

4 0
2 years ago
Anna will wear a black dress when she attends her cousin’s wedding. Which color(s) does the dress absorb?
storchak [24]
As the dress is black it will absorb all colors with all different wavelengths

In short, Your Answer would be Option A

Hope this helps!
6 0
3 years ago
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Find the area of the part of the plane 5x 3y z = 15 that lies in the first octant.
Lunna [17]

This part of the plane lies above a triangle with boundaries x=0 and y=0 along the coordinate axes, as well as the line

z=0 \implies 5x + 3y = 15 \implies y = \dfrac{15 - 5x}3

When y=0, we have 15-5x=0\implies x=3. So this triangle is the set

T = \left\{(x,y)\in\Bbb R^2 ~:~ 0\le x\le3 \text{ and } 0\le y\le\dfrac{15-5x}3\right\}

Also, when x=0, we have y=\frac{15}3=5. So the triangle has length 3 and width 5, hence area 1/2•3•5 = 15/2.

Let z=f(x,y) = 15 - 5x - 3y. Then the area of the plane over T is

\displaystyle \iint_T dA = \iint_T \sqrt{1 + \left(\frac{\partial f}{\partial x}\right)^2 + \left(\frac{\partial f}{\partial y}\right)^2} \, dx \, dy

We have

\dfrac{\partial f}{\partial x} = -5 \implies \left(\dfrac{\partial f}{\partial x}\right)^2 = 25

\dfrac{\partial f}{\partial y} = -3 \implies \left(\dfrac{\partial f}{\partial y}\right)^2 = 9

\implies\displaystyle \iint_T dA = \sqrt{35} \iint_T dx\,dy = \boxed{\frac{15\sqrt{35}}2}

since the integral

\displaystyle \iint_TdA

is exactly the area of T, 15/2.

8 0
1 year ago
Explain how the "natural frequency" of objects must be considered/analyzed in places like concert halls and airplanes.
hjlf
If you are talking about sound frequency you need to consider what area you are in because in a concert hall it is big and helps the sound spread but in an airplane it is the opposite. 
5 0
2 years ago
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