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lara [203]
2 years ago
15

Starting from rest, a 5.00 kg steel sphere rolls down a frictionless ramp with a height of 4.00 m. What is the sphere's speed wh

en it reaches the bottom of the ramp? (Use 9.80 for the value of "g.")
Physics
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

Answer:

8.85437 m/s

Explanation:

m = Mass of sphere = 5 kg

h = Vertical height = 4 m

g = Acceleration due to gravity = 9.80 m/s²

Applying conservation of energy we get

\dfrac{1}{2}mv^2=mgh

\\\Rightarrow v=\sqrt{2gh}

\\\Rightarrow v=\sqrt{2\times 9.8\times 4}

\\\Rightarrow v=8.85437\ m/s

The sphere's speed when it reaches the bottom of the ramp is 8.85437 m/s

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An object is accelerating if there is a change in speed and/or ________.
Alborosie

Acceleration means any change in the speed or direction of motion.
8 0
3 years ago
Read 2 more answers
1)the car's engine power is 44000W. Explain this number in a physical sense
Ratling [72]

Answer:

1) It expresses the rate (top speed) at which it can move with time.

2) P = 20 W

3) h = 18 km

Explanation:

1) Power is the rate of transfer of energy.

⇒ Power = \frac{Energy(or workdone)}{Time}

i.e P = \frac{E}{t}

Thus a car's engine power is 44000W implies that the engine of the car can propel the car at this rate. This expresses the rate (top speed) at which it can move with time.

2) m = 400g = 0.4 kg

    t = 20 s

h = 100m

g = 10 m/s^{2}

P = \frac{mgh}{t}

  = \frac{0.4*10*100}{20}

  = \frac{400}{20}

P = 20 W

3) u = 600 m/s

   g = 10 m/s^{2}

From the third equation of free fall,

V^{2} = U^{2} - 2gh

V is the final velocity, U is the initial velocity, h is the height.

0 = (600)^{2} - 2 x 10 x h

0 = 360000 - 20h

20h = 360000

h = \frac{360000}{20}

  = 18000

h = 18 km

The maximum height of the bullet would be 18 km.

3 0
3 years ago
When we apply the energy conversation principle to a cylinder rolling down an incline without sliding, we exclude the work done
NikAS [45]

Answer:

D. the linear velocity of the point of contact (relative to the inclined surface) is zero

Explanation:

The force of friction emerges only when there is relative velocity between two objects . In case of perfect rolling , there is no sliding so relative velocity between the surface and the point of contact is zero . In other words the velocity of point of contact becomes zero , even though , the whole body is in linear motion . It happens due  point of contact having two velocities which are equal and opposite . One of the velocity is in forward direction and the other velocity which is due to rotation is in backward direction . So net velocity of point of contact becomes zero . Due to absence of sliding , displacement due to friction  becomes zero . Hence work done by friction becomes zero.

5 0
3 years ago
Please help<br> question #70
Keith_Richards [23]

can i get the question so that i can answer your question

8 0
3 years ago
You are testing a new amusement park roller coaster with an empty car with a mass 120 kg. One part of the track is a vertical lo
Kay [80]

Answer:

- 5436 J

Explanation:

mass of car, m = 120 kg

radius of loop, r = 12 m

velocity at the bottom (A) = Va = 25 m/s

Velocity at the top(B) = Vb = 8 m/s

Vertical distance from A to B = diameter of loop, h = 2 x 12 = 24 m

by use of Work energy theorem

Work done by all the forces = change in kinetic energy of the body

Work done by the force + Work done by the friction = Kinetic energy at B - kinetic energy at A

- m x g x h + Work done by friction = 0.5 x 120 x (Vb^2 - Va^2)

- 120 x 9.8 x 24 + Work done by friction = 60 x (64 - 625)

- 28224 + Work done by friction = - 33660

Work done by friction = -33660 + 28224 = - 5436 J

4 0
3 years ago
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