Question

Starting from rest, a 5.00 kg steel sphere rolls down a frictionless ramp with a height of 4.00 m. What is the sphere's speed when it reaches the bottom of the ramp? (Use 9.80 for the value of "g.")

Answer 1

Answer:

8.85437 m/s

Explanation:

m = Mass of sphere = 5 kg

h = Vertical height = 4 m

g = Acceleration due to gravity = 9.80 m/s²

Applying conservation of energy we get

$\dfrac{1}{2}mv^2=mgh$

$\\\Rightarrow v=\sqrt{2gh}$

$\\\Rightarrow v=\sqrt{2\times 9.8\times 4}$

$\\\Rightarrow v=8.85437\ m/s$

The sphere's speed when it reaches the bottom of the ramp is 8.85437 m/s