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lara [203]
3 years ago
15

Starting from rest, a 5.00 kg steel sphere rolls down a frictionless ramp with a height of 4.00 m. What is the sphere's speed wh

en it reaches the bottom of the ramp? (Use 9.80 for the value of "g.")
Physics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

Answer:

8.85437 m/s

Explanation:

m = Mass of sphere = 5 kg

h = Vertical height = 4 m

g = Acceleration due to gravity = 9.80 m/s²

Applying conservation of energy we get

\dfrac{1}{2}mv^2=mgh

\\\Rightarrow v=\sqrt{2gh}

\\\Rightarrow v=\sqrt{2\times 9.8\times 4}

\\\Rightarrow v=8.85437\ m/s

The sphere's speed when it reaches the bottom of the ramp is 8.85437 m/s

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Trava [24]
The equation Q=CV (Charge = product of Capacitance and potential difference) tells us that the maximum charge that can be stored on a capacitor is equal to the product of it's capacitance and the potential difference across it. In this case the potential difference across the capacitor will be 12.0V (assuming circuit resistance is negligable) and it has a capacitance of 18.0μf or  18.0x10^-6f, therefore charge equals (18.0x10^-6)x12=2.16x10^-4C (Coulombs).
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2 years ago
A driver travels 225 miles in 4 hours and 30 minutes. What was his average speed in mph?
andrew-mc [135]

Answer:

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8 0
3 years ago
Find electric field at point p which is a distance l away from the both +q and -q
denis-greek [22]

Answer:

\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

Explanation:

As given point p is equidistant from both the charges

It must be in the middle of both the charges

Assuming all 3 points lie on the same line

Electric Field due a charge q at a point ,distance r away

=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{r^{2} }

Where

  • q is the charge
  • r is the distance
  • E is the permittivity of medium

Let electric field due to charge q be F1 and -q be F2

I is the distance of P from q and also from charge -q

⇒

F1=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }

F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

⇒

F1+F2=\frac{1}{4\times(pie)\times\text{E}} \times\frac{q}{I^{2} }+\frac{1}{4\times(pie)\times\text{E}} \times\frac{-q}{I^{2} }

8 0
3 years ago
These capacitors are then disconnected from their batteries, and the positive plates are now connected to each other and the neg
Kay [80]

Answer:

Following are the solution to the given question:

Explanation:

For charging plates that are connected in a similar manner:

Calculating the total charge:

\to q =q_1 + q_2 = C_1V_1 +C_2V_2 =1320 + 2714 = 4034 \mu C

Calculating the common potential:

\to V = \frac{q}{C}= \frac{q}{(C_1 + C_2)} =\frac{4034}{6.8} = 593 \ V\\\\

Calculating the charge after redistribution:

When: \\\\q = q_{1}' + q_{2}' = q_1 + q_2        

\to q_{1}' = C_1V = 2.2 \times 593 = 1305\ \mu C\\  \\  \to               q_{2}' = C_2V = 4.6 \times 593 = 2729 \ \mu C

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3 years ago
PLZ! PLZ! PLZ! HELP! WILL GIVE BRAINLIEST! Scientific Claim Engaging in scientific argument is a critical piece to the applicati
Nastasia [14]

Answer:

Explanation:

1The study of science and engineering should produce a sense of the process of argument necessary for advancing and defending a new idea or an explanation of a phenomenon and the norms for conducting such arguments. In that spirit, students should argue for the explanations they construct, defend their interpretations of the associated data, and advocate for the designs they propose. (NRC Framework, 2012, p. 73)

Argumentation is a process for reaching agreements about explanations and design solutions. In science, reasoning and argument based on evidence are essential in identifying the best explanation for a natural phenomenon. In engineering, reasoning and argument are needed to identify the best solution to a design problem. Student engagement in scientific argumentation is critical if students are to understand the culture in which scientists live, and how to apply science and engineering for the benefit of society. As such, argument is a process based on evidence and reasoning that leads to explanations acceptable by the scientific community and design solutions acceptable by the engineering community.

Argument in science goes beyond reaching agreements in explanations and design solutions. Whether investigating a phenomenon, testing a design, or constructing a model to provide a mechanism for an explanation, students are expected to use argumentation to listen to, compare, and evaluate competing ideas and methods based on their merits. Scientists and engineers engage in argumentation when investigating a phenomenon, testing a design solution, resolving questions about measurements, building data models, and using evidence to evaluate claims.

Compare and critique two arguments on the same topic and analyze whether they emphasize similar or different evidence and/or interpretations of facts.

Respectfully provide and receive critiques about one’s explanations, procedures, models and questions by citing relevant evidence and posing and responding to questions that elicit pertinent elaboration and detail.

Construct, use, and/or present an oral and written argument supported by empirical evidence and scientific reasoning to support or refute an explanation or a model for a phenomenon or a solution to a problem.

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2 years ago
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