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3 years ago

5. A ski slope is 310 yards long with a vertical drop of 220 yards. Find the

1 answer:

6 0

It helps to draw a picture so you can see which trig ratios to use but...

310 is the hypotenuse of the ski slope and the side length across from the angle you’re looking for is 220, the vertical drop.

You can use sin to find theta.

sinx= 220/310

sinx=0.70967...
x = sin inverse of 0.70967....
x = 45°

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Four times the larger of two numbers is equal to seven times the smaller the sum of the numbers is 22 find the numbers

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8 and 14

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3 years ago

15. (3x + 6) - (3x - 6)

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You want to buy a car, and a local bank will lend you $30,000. The loan would be fully amortized over 6 years (72 months), and t

Georgia [21]

Answer:

<h2>- 56,667cents</h2><h2>- 6.17%</h2>

Step-by-step explanation:

Before we can determine the monthly loan paymnet, we must first calculate the total amount paid at the end of 6years.

Amount = Principal + Interest

Given Principal = $30,000

Interest = Principal * rate * time/100

Interest = $30,000*6*6/100

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Amount = $30,000+ $10,800

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If amount paid after 6years is $40,800, my monthly loan payment = $40,800/72 ≈ $566.67 to nearest dollar.

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EFF = (1 + r /n)^n - 1

r is the rate and n is the number of period per year which is 12months

%EFF = EAR = (1 + 0.06 /12)^ 12 - 1

%EFF = 1.005^12

%EFF = 1.061678 - 1

%EFF = 0.061678

%EFF = 6.17% to 2dp

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3 years ago

Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes

azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

The centre of the ellipse is at the origin and the X axis is the major axis

It passes through the points (-3, 1) and (2, -2)

The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

$\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1$

Given that the ellipse passes through the point (-3, 1)

Hence,

$\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1$

Cross multiplying we get,

9b² + a² = 1 ²× a²b²
a²b² = 9b² + a²

Multiply by 4 on both sides,

4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

$\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1$

Cross multiply,

4b² + 4a² = 1 × a²b²
a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

3a²b² = 32b²
3a² = 32
a² = 32/3----(3)

Substituting in 2,

32/3 × b² = 4b² + 4 × 32/3
32/3 b² = 4b² + 128/3
32/3 b² = (12b² + 128)/3
32b² = 12b² + 128
20b² = 128
b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

$\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1$

$\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1$

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>

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3 years ago