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FinnZ [79.3K]
3 years ago
8

What mass of oxygen contains the same number of molecules as 42g of nitrogen?

Chemistry
1 answer:
lakkis [162]3 years ago
3 0

Answer:

Given: 42 g of N2

Solve for O2 mass that contains the same number of molecules to 42 g of N2.

Solve for the number of moles in 42 g of N2

1 mole of N2 = (14 * 2) g = 28 g so the number of moles in 42 g of N2 is equal to 42 g / 28 g per mole = 1.5 moles

Solve for mass of 1 mole of oxygen

1 mole of O2 = 16 g * 2 = 32 g per mole

Solve for the mass of 1.5 moles of oxygen

mass of 1.5 moles of O2 = 32 g per mole * 1.5 moles

mass of 1.5 moles of O2 = 48 g

So 48 g of O2 contains the same number of molecules as 42 g of N2

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Ethylene produced by fermentation has a specific gravity of 0.787 at 25 degree Celsius. What is the volume of 125g of ethanol at
WITCHER [35]

<u>Answer:</u> The volume of given amount of ethanol at this temperature is 159.44 mL

<u>Explanation:</u>

Specific gravity is given by the formula:

\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}

We are given:

Density of water = 0.997 g/mL

Specific gravity of ethanol = 0.787

Putting values in above equation, we get:

0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL

Density is defined as the ratio of mass and volume of a substance.

\text{Density}=\frac{\text{Mass}}{\text{Volume}} ......(1)

Given values:

Mass of ethanol = 125 g

Density of ethanol = 0.784 g/mL

Putting values in equation 1, we get:

\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL

Hence, the volume of given amount of ethanol at this temperature is 159.44 mL

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A scooter maintains a pace of 1.45 minutes per mile, with fuel economy of 85 miles per gallon. How many seconds can it travel on
vlada-n [284]

Answer:

281s

Explanation:

Given parameters:

Speed of the scooter  = 1.45min per mile

Fuel economy of engine  = 85miles per gallon

Quantity of fuel  = 145mL

Unknown:

Time of travel with the volume of fuel given  = ?

Solution:

To solve this problem, we need to find the distance the fuel will last.

 Rate of fuel consumption by the engine  = 85miles per gallon

Convert 145mL to gallons;

                3785.41mL  = 1 gallon

               145mL will therefore give \frac{145}{3785.41}    = 0.038gallons

So;

   Distance covered  = 85miles per gallon  x 0.038gallons  = 3.23miles

From;

             Rate of travel  = \frac{time }{distance}  

       Time  = rate of travel x distance  = 1.45 minutes per mile x  3.23miles

     Time  = 4.7min

             1 min  = 60s

            4.7min  = 4.7 x 60 = 281s

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2 years ago
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