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Maru [420]
3 years ago
5

When measuring water using the graduated pipette, the mass of beaker and the water is 23.670 g. If the empty beaker weighs 13.71

2 g. What is the volume of water measured assuming a density of 0.9982071 g/mL.
Chemistry
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

The volume of water measured is 10mL

Explanation:

Given;

Mass of mass of beaker and the water = 23.670 g

Mass of empty beaker = 13.712 g

Then, mass of water only = Total mass of of beaker and the water minus Mass of empty beaker

mass of water only = 23.670 g - 13.712 g = 9.958 g

Density = mass/volume

Given density of water = 0.9982071 g/mL

Density of water = Mass of water/ Volume of water

Then, Volume of water =  Mass of water/Density of water

Volume of water = 9.958 g/0.9982071 g/mL

Volume of water = 9.975886 mL ≅ 10mL

Therefore, The volume of water measured is 10mL

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What is the molarity of a solution that contains 15.0g of naoh per 500.0 ml of solution ​
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Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,  

NaOH

, divided by liters of solution.

molarity

=

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,  

mL

.

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

7

g

⋅

1 mole NaOH

40.0

g

=

0.175 moles NaOH

The volume of the solution in liters will be

500

mL

⋅

1 L

1000

mL

=

0.5 L

Therefore, the molarity of the solution will be

c

=

n

V

c

=

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=

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8 0
3 years ago
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