Answer:
Move all terms that don't contain y to the right side and solve.
y = 3 + 4
x
1 and 2 are equations and 3 is a solution
3x² - 39x + 36
3(x²) - 3(13x) + 3(12)
3(x² - 13x + 12)
3(x² - 12x - x + 12)
3(x(x) - x(12) - 1(x) + 1(12))
3(x(x - 12) - 1(x - 12))
3(x - 1)(x - 12)
Answer:
B
Step-by-step explanation:
since 5 is constant so you can take it out from the summation
