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Sergio [31]
2 years ago
8

Please help

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
8 0

Answer:

270 coins

n + p

Step-by-step explanation:

Given that :

Number of nickels = 140

Number of pennies = 130

The total numbers coins had:

Number of Nickel + number of pennies

140 + 130 = 270 coins

If Number of nickels = n ; number of pennies = p

The total number of coins :

Number of Nickel + number of pennies

n + p

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castortr0y [4]
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<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em><em> ❤️</em>

8 0
3 years ago
-8x^2-3x+5+2x^2+7x-5
denis-greek [22]
-6x^2+4x

my reasoning:
eliminate the opposites (5 & -5)
collect the like terms (-8x^2 & + 2x^2)
collect the like terms again (-3x &+7x)
8 0
3 years ago
Will 4 5/10 x 6/17 be larger, smaller, the same or impossible to tell than 4 5/10?
Delicious77 [7]
4¹/₂ × ⁶/₁₇
⁹/₂ × ⁶/₁₇
²⁷/₁₇
1¹⁰/₁₇

The product of 4¹/₂ and ⁶/₁₇ will be smaller than 4¹/₂.
3 0
3 years ago
A solution of the equation x^2/4=9 is
abruzzese [7]

Answer:

x = ±6

Step-by-step explanation:

x^2/4=9

Multiply by 4 on each side

x^2/4 *4=9*4

x^2 = 36

Take the square root of each side

sqrt(x^2) = ±sqrt(36)

x = ±6

5 0
3 years ago
An electric company has to track on-time payments and late payments for each customer monthly. It is impossible for a customer t
OLga [1]

Answer:

The  probability that a customer pays late each month is    P(B)  =  0.27

Step-by-step explanation:

Let     P( A ) be the probability that the customer pays on time and the value is  0.55

Let  P( B )  be the  probability that a customer pays late each month

So

  The probability that a customer pays late or on-time each month  is  P(A u B) and  the value is  0.82

The probability that a customer pays on-time and late each month is  P(A n B) and  the value is  zero ( 0 ) given that it is impossible

   Now The probability that a customer pays late or on-time each month  is mathematically represented as

      P(A u B)  =  P(A) +  P(B)  -   P(A n B)

=>     0.82  =  0.55 + P( B ) -   0

=>    P(B)  =  0.27

8 0
3 years ago
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