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3 years ago

Please help

Mathematics

1 answer:

goldfiish [28.3K]3 years ago

8 0

Answer:

270 coins

n + p

Step-by-step explanation:

Given that :

Number of nickels = 140

Number of pennies = 130

The total numbers coins had:

Number of Nickel + number of pennies

140 + 130 = 270 coins

If Number of nickels = n ; number of pennies = p

The total number of coins :

Number of Nickel + number of pennies

n + p

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URGENT

Zepler [3.9K]

Answer: The volume of a sphere with a radius of 5 cm is approximately 523.33 cm3.

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Volume of a sphere (V) = 4/3 π radius³

Replacing with the values given and solving for V (volume)

V = 4/3 (3.14) 5³ = 4/3 (3.14) 125= 523.33 cubic centimeters

The volume of a sphere with a radius of 5 cm is approximately 523.33 cm3.

Feel free to ask for more if needed or if you did not understand something.

4 0

3 years ago

Triphasil-28 birth control tablets are taken sequentially, 1 tablet per day for 28 days, with the tablets containing the followi

bazaltina [42]

Answer:

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

Step-by-step explanation:

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3}$

In which $L_{1}, L_{2}$ and $L_{3}$ are the number of miligrams of levonorgestrel taken in each phase.

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3}$

In which $E_{1},E_{2}$ and $E_{3}$ are the number of miligrams of ethinyl estradiol taken in each phase.

We can solve this by phase.

Phase 1: 6 tablets, each containing 0.050 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$6*0.050mg = 0.30mg$ of levonorgestrel and $6*0.030mg = 0.18mg$ of ethinyl estradiol are taken.

So $L_{1} = 0.30$ and $E_{1} = 0.18$

Phase 2: 5 tablets, each containing 0.075 mg of levonorgestrel and 0.040 mg ethinyl estradiol

In this phase,

$5*0.075mg = 0.375mg$ of levonorgestrel and $5*0.040mg = 0.20mg$ of ethinyl estradiol are taken.

So $L_{2} = 0.375$ and $E_{2} = 0.20$

Phase 3: 10 tablets, each containing 0.125 mg of levonorgestrel and 0.030 mg ethinyl estradiol

In this phase,

$10*0.125mg = 1.25mg$ of levonorgestrel and $10*0.030mg = 0.30mg$ of ethinyl estradiol are taken.

So $L_{3} = 1.25$ and $E_{3} = 0.30$

The total milligrams of levonorgestrel is:

$L = L_{1} + L_{2} + L_{3} = 0.30 + 0.375 + 1.25 = 1.925$

The total milligrams of ethinyl estradiol is:

$E = E_{1} + E_{2} + E_{3} = 0.18 + 0.20 + 0.30 = 0.68$

1.925mg of levonorgestrel and 0.68mg of ethinyl estradiol are taken during the 28-day period.

6 0

3 years ago

Factor the expression using the GCF. 18h+30k The factored form is .

Murljashka [212]

Answer:

6(3h+5k)

Step-by-step explanation:

18h+30k

Factors of 18:

1, 2, 3, 6, 9, 18

Factors of 30:

1, 2, 3, 5, 6, 10, 15, 30

GCF of 18 and 30: 6

18h+30k = 6(3h+5k)

Check your answer:

6(3h+5k)

6(3h) + 6(5k)

18h + 30k

Hope this helps!

7 0

2 years ago

67 to the 2nd power, plz tell me if the answer is a prime number Who wants to t a l k

Galina-37 [17]

Answer:

No, it is not prime.

Step-by-step explanation:

67^2 = 4489

A number cannot be prime if it is divisible by a number besides 1 and itself. 4489 is divisible by 67; no perfect square can be prime.

8 0

2 years ago

Investigate the difference between compounding annually and simple interest

Gennadij [26K]

Step-by-step explanation:

Simple interest formula

$A = P (1 + rt)$

Compound interest formula

$A = P(1 + \frac{r}{n})^{nt}$

$A = 5000 (1 + 0.025*1)\\A=5000(1.025)\\A=5125$

Simple interest is $125

. $A = 5000 (1 + \frac{0.025}{1})^{1*1} \\A=5000(1.025)\\A= 5125$

Compound interest is $125

c. the result for both a and b are the same

$A = 5000 (1 + 0.025*3) \\A=5000(1.075) \\A=5375$

the simple interest is $375

. $A = 5000 (1 + \frac{0.025}{1})^{1*3}] \\A=5000(1.025)^3 \\A=5000(1.077)\\A= 5385$

the compound interest is $385

f. the result compared, compound interest is $10 more than simple interest

$A = 5000 (1 + 0.02*6) \\A=5000(1.12) \\A=5600$

the simple interest is $600

$A = 5000 (1 + \frac{0.02}{1})^{1*6}] \\A=5000(1.12)^6 \\A=5000(1.9738) \\A= 9869$

the compound interest is $4869

i. the result from g and h, h is over 8 times bigger than g.

j. interest compound annually is not the same as simple interest, only for the case of a and b seeing that it is for 1 year. but for 2years and above there is difference as seen in c to h

6 0

3 years ago