Answer : The correct answer is option 2 : 0.10 M NaCl and 0.10 M NaClO₄
Explanation :
Solutions are classified into 3 categories.
1) Strong electrolytes : These are the solutions that dissociate completely forming ions . They are good conductors of electricity.
Example : All strong acids, bases and the salts made by strong acid/base are strong electrolytes .
2) Weak electrolytes : These substances do not dissociate completely thereby forming fewer ions. They are weak conductors of electricity.
3) Non electrolytes : These are the substances that do not dissociate at all. They do not form ions in aqueous medium. They are bad conductors of electricity.
Let us take a look at the given options and find out what type of solution do we have .
Option 1 : NH₃ is a weak electrolyte whereas NH₄Cl is a strong electrolyte bcause NH₄Cl is made by combination of NH₃ and HCl ( HCl is a strong acid)
Therefore NH₃ would carry electricity less efficiently than NH₄Cl.
Option 2 : Both NaCl and NaClO₄ are strong electrolytes. Therefore they will conduct electrical current equally well
Option 3 : NaNO₃ is a strong electrolyte but HNO₂ is a weak electrolyte. Therefore they will not carry the current equally
Therefore the correct option is option 2
I think this is correct
Copper(II) Phosphite Cu3(PO3)2 Molecular Weight -- EndMemo.
Answer:
2.28 g of CsF.
Explanation:
The following data were obtained from the question:
Molar mass of CsF = 151.9 g/mol.
Volume = 300 mL
Molarity of CsF = 0.05 M
Mass of CsF =.?
Next, we shall convert 300 mL to litre (L). This can be obtained as follow:
1000 mL = 1 L
Therefore,
300 mL = 300 mL /1000 mL × 1 L
300 mL = 0.3 L
Therefore, 300 mL is equivalent to 0.3 L
Next, we shall determine the number of mole CsF in the solution. This can be obtained as follow:
Volume = 0.3 L
Molarity of CsF = 0.05 M
Mole of CsF =.?
Molarity = mole /Volume
0.05 = mole of CsF /0.3
Cross multiply
Mole of CsF = 0.05 × 0.3
Mole of CsF = 0.015 mole.
Finally, we shall determine the mass of CsF needed to prepare the solution as follow:
Mole of CsF = 0.015 mole.
Molar mass of CsF = 151.9 g/mol.
Mass of CsF =.?
Mole = mass /Molar mass
0.015 = mass of CsF /151.9
Cross multiply
Mass of CsF = 0.015 × 151.9
Mass of CsF = 2.28 g
Therefore, 2.28 g of CsF is needed to prepare the solution.
When multiple data streams are collected, one must decide how those data will be fused in the decision process. Separate data streams can be:
Mixed mode (including both quantitative and qualitative data).
Redundant (validating the data from another stream).
Complementary (providing measures of multiple characteristics of an object).
Supportive (helping verify some interpretation of another data stream).
Answer:
We need 247 mL of NaOH
Explanation:
Step 1: Data given
Molarity of NaOH = 0.587 M
Volume of 0.445 M NiBr2 solution = 163 mL = 0.163 L
Step 2: The balanced equation
NiBr2(aq) + 2NaOH(aq) Ni(OH)2(s) + 2NaBr(aq)
Step 3: Calculate moles of NiBr2
Moles NiBR2 = Molarity NiBR2 * volume
Moles NiBR2 = 0.445 M * 0.163 L
Moles NiBR2 = 0.0725 moles
Step 3: Calculate moles of NaOH
For 1 mol NiBr2 consumed, we need 2 moles NaOH
For 0.0725 moles NiBR2, we need 2* 0.0725 = 0.145 moles NaOH
Step 4: Calculate volume of NaOH
Volume = moles NaOH / Molarity NaOH
Volume = 0.145 moles / 0.587 M
volume = 0.247L = 247 mL
We need 247 mL of NaOH
