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stich3 [128]
3 years ago
11

True or False? Elements in the same row have similar properties. Question 4 options: True False

Chemistry
2 answers:
Natasha2012 [34]3 years ago
6 0
4. false
5. true
6.valence electrons

I took the test
 
Hope this helps.
Gekata [30.6K]3 years ago
3 0

1) Answer is: False.

A period in the periodic table is a horizontal row. For example, sodium and chlorine are in third period and they have very different properties. Sodium is solid metal and chlorine is gaseous nonmetal. Elements in the same row have the same number of electron shells, but different proporties.

2) Answer is: True.

Group is a column of elements in the periodic table. For example, lithium and sodium are in 1 group of the periodic table and they both have one valence electron.

3) Answer is: valence electrons.

For example, electron configuration of oxygen atom: ₈O 1s² 2s² 2p⁴.

Oxygen atom has six valence electrons, so it is in 16 group of Periodic table of elements.


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How many grams are in 6.8L of Oxygen gas (O2) at STP
zubka84 [21]

Answer:

9.7 g

Explanation:

From the question,

Note: The molar volume of all gas at stp is 22.4 dm³ or 22.4 L

1 mol of  oxygen gas (O₂) at stp = 22.4 dm³

X mole of oxygen gas (O₂) at stp = 6.8 L

X = (1 mol×6.8 L)/22.4 L

X = 0.3036 mol.

But,

Number of mole (n) = mass (m)/molar mass (m')

n = m/m'

m = n×m'.................. Equation 2

Where n = 0.3036 mol, m' = 32 g/mol

Substitute into equation 2

m = 0.3036×32

m = 9.7 g

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3 years ago
What quantity is the same among atoms of the same element?
Vedmedyk [2.9K]

Answer:

Neutrons or Neutral atoms

Explanation:

Neutral atoms of each element contain an equal number of protons and electrons. The number of protons determines an element's atomic number and is used to distinguish one element from another.

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2 years ago
What is the concentration of a 0.750 l solution that contains 52.0 g of glucose (c6h12o6)?
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Concentration of Solutions is oftenly expressed in Molarity. Molarity is the number of moles of solute dissolved per volume of solution.

                             Molarity  =  Moles / Volume
As,
      Moles  =  Mass / M.mass
So,
                             Molarity  =  Mass / M.mass × Volume   ---- (1)

Data Given;
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                   Mass  =  52 g

                   M.mass  =  180 g/mol

Putting Values in eq.1,

                     Molarity  =  52 g ÷ (180 g.mol⁻¹ × 0.750 L)

                     Molarity  =  0.385 mol.L⁻¹
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