Answer:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Explanation:
AlF₃ + Li₂O —> Al₂O₃ + LiF
The above equation can be balanced as follow:
AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 2 atoms of Al on the right side and 1 atom on the left side. It can be balance by writing 2 before AlF₃ as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + LiF
There are 6 atoms of F on the left side and 1 atom on the right side. It can be balance by writing 6 before LiF as shown below:
2AlF₃ + Li₂O —> Al₂O₃ + 6LiF
There are 2 atoms of Li on the left side and 6 atoms on the right side. It can be balance by writing 3 before Li₂O as shown below:
2AlF₃ + 3Li₂O —> Al₂O₃ + 6LiF
Thus, the equation is balanced..!
Answer:
ΔT = 76.5 °C
Explanation:
Given data:
Amount of water = 100.0 g
Energy needed = 32000 J
Change in temperature = ?
Solution,
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Now we will put the values in formula.
Q = m.c. ΔT
ΔT = Q / m.c
ΔT = 32000 j/ 100.0 g × 4.184 j/g. °C
ΔT = 32000 j / 418.4 j /°C
ΔT = 76.5 °C
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The molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
<h3>How to calculate molarity?</h3>
The molarity of a solution can be calculated using the following formula:
M1V1 = M2V2
Where;
- M1 = molarity of a base
- M2 = molarity of acid
- V1 = volume of base
- V2 = volume of acid
M1 × 200 = 50 × 5
200M1 = 250
M1 = 250/200
M1 = 1.25M
Therefore, the molarity of a solution formed when you add 200 mL of water to 50 mL of 5. 0 M HCl is 1.25M.
Learn more about molarity at: brainly.com/question/12127540