The concentration of iron used in the titration : 0.009 M
<h3>Further explanation</h3>
Given
Reaction
Cr₂O₇²⁻ + 6Fe²⁺ + 14H⁺ ⇒ 2Cr³⁺ + 6Fe³⁺ + 7H₂O
0.0093 mol/L potassium dichromate
200 cm³ of dilute acid, 25cm³ was used in the titration.
Required
the concentration of iron
Solution
Titration formula
C₁V₁n₁=C₂V₂n₂⇒ From equation : n₁=6n₂(1=Cr₂O₇, 2=Fe)
titration average : 33+32.05+32.15+32.1 / 4 = 32.325 cm³(ml)
25 cm³ of iron solution used in titration :
Dilution(25 ml from 200 ml iron solution)
Answer:
elements have the same number of valence electrons and similar chemical properties.
Explanation:
they have the same number
Answer:
22.9g of H₂O are produced
Explanation:
The reaction of hydrogen with oxygen is:
2H₂(g) + O₂(g) → 2H₂O(g)
<em>Where 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water</em>
<em />
Moles of hydrogen are:
2.56g × (1mole / 2.01g) = <em>1.27moles H₂</em>
Moles of oxygen are:
20.3g × (1mole / 32g) = <em>0.634moles O₂</em>
These moles of oxygen react with:
0.634moles O₂ × (2mol H₂ / 1mol O₂) =<em> 1.27mol H₂</em>
<em>-All hydrogen in reaction-</em>
And produce:
0.634moles O₂ × (2mol H₂O / 1mol O₂) =<em> 1.27mol H₂O</em>
In grams:
1.27mol <em>H₂O </em>× (18.01g / 1mol) = <em>22.9g of H₂O are produced</em>
Answer:
0.13 J/g.°C.
Explanation:
- To solve this problem, we can use the relation:
<em>Q = m.c.ΔT,</em>
where, Q is the amount of heat absorbed by lead (Q = 29.0 J).
m is the mass of lead (m = 15.0 g).
c is the specific heat capacity of lead (c = ??? J/g.°C).
ΔT is the temperature difference (final T - initial T) (ΔT = 37 °C - 22 °C = 15.0 °C).
∵ Q = m.c.ΔT
<em>∴ c = Q/m.ΔT </em>= (29.0 J)/(15.0 g)(15.0 °C) = <em>01288 J/g.°C ≅ 0.13 J/g.°C.</em>
A. The electron moves from a lower to a higher energy orbital
