Question

Iron (III) oxide reacts with carbon monoxide to produce iron metal and carbon dioxide. What mass of iron is produced from the reduction of 10.0 g of iron (III) oxide.

Answer 1

Answer:

7 grams of iron is produced from the reduction of 10.0 g of iron (III) oxide.

Explanation:

$Fe_2O_3+3CO\rightarrow 3CO_2+2Fe$

Moles of iron (III) oxide :

$\frac{10.0g}{160 g/mol}=0.0625 mol$

According to reaction, 1 mol of iron(III) oxide gives 2 moles of iron metal.

Then 0.0625 moles of iron(III) oxide will give:

$\frac{2}{1}\times 0.0625 mol=0.125 mol$ of iron metal.

Mass of 0.125 moles of iron metal.

$0.125 mol\times 56 g/mol=7 g$

7 grams of iron is produced from the reduction of 10.0 g of iron (III) oxide.