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givi [52]
3 years ago
13

What is the best reason for a student to remove a dangling bracelet when heating test tubes of acidic solutions in a hot water

Physics
2 answers:
jarptica [38.1K]3 years ago
7 0

Answer: To minimize the chance the bracelet pulling over a test tube, causing a spill.

Explanation:

A chemistry lab is a laboratory where the potential hazards related to the chemicals may result if safety precautions are neglected. The chances of the cause of chemical splash, burns from chemicals or fire hazards can possibly  happen in a chemistry lab. The use of ornaments should be avoided in the chemical lab. Proper safety measures are to be taken to protect the body from chemical hazards by wearing close toed shoes, lab coat and gloves.

A dangling bracelet worn during the heating process is likely to spill off the acid solutions by pulling over a test tube. The test tube neck may get caught in the dangling bracelet. The test tube may collapse and break. Thus the dangling bracelet should be avoided during the process of heating.

soldi70 [24.7K]3 years ago
4 0

Answer:

c

Explanation:

this equestion is about the safety

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Nosebleeds can be caused by being up in a very high altitude. As you climb higher, the amount of oxygen in the air decreases. This makes the air thinner and dryer, which can in turn cause the inside of your nose to crack and bleed.F
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Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as h
Arturiano [62]

Answer:

A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.

So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.

So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle

As we know that arc length is given as

L = R\theta

length of chord is given as

L_c = 2Rsin(\frac{\theta}{2})

so here

L > L_c

R\theta > 2R sin(\frac{\theta}{2})

so we have

\frac{\theta}{2} > sin(\frac{\theta}{2})

6 0
3 years ago
The distance from one crest to the next is the ________.
nikitadnepr [17]

Answer:

Wavelength.

Explanation:

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7 0
4 years ago
two ships leave a port at the same time. The first ship sails on a bearing of 40 degrees at 18 knots and the second at a bearing
Yuliya22 [10]

Answer:

The distance between the ships is 87.84 km.

Explanation:

Given that,

Angle of first ship= 40°

Speed of first ship = 18 knots

Angle of second ship= 130°

Speed of second ship = 26 knots

We need to calculate the resultant velocity

Using cosine rule

v=\sqrt{v_{1}^2+v_{2}^2-2v_{1}v_{2}\cos\theta}

Put the value into the formula

v=\sqrt{18^2+26^2-2\times18\times26\times\cos90}

v=\sqrt{18^2+26^2}

v=\sqrt{324+676}

v=10\sqrt{10}

We need to calculate the distance between the ships

d =v\times t

Put the value into the formula

d=10\sqrt{10}\times1.5\times1.852

d=87.84\ km

Hence, The distance between the ships is 87.84 km.

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3 years ago
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rosijanka [135]
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