How far would a runner that ran 200 meters in minute run in 3 minutes at the same rate?
2 answers:
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Answer:
149 engines in 9th year
Step-by-step explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one.
Please have a look at the attached photo.
My answer:
From a look at the photo and the data plot can be represented by the function, so we can pick 2 points in our given graph
- (x1, y1) = (2,60)
- (x2, y2) = (5,99)
The standard form of a linear equation is:
y = mx + b where:
- m is the slope
- b is the y-intercept
We know the slope of the function can be found as following:
so in this situation we have:
<=>
=> y = 13x + b (1)
Because the line goes through point (2,60) so we substitute it into (1):
60 = 13*2 + b
<=> b = 60 - 26 = 34
=> y = 13x + 34
Now we will substitute x=9 to find the engines produced by company in 9th year as:
Hence, the company will produce 149 engines in 9th year
