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mamaluj [8]
3 years ago
6

What are the steps for this and the answer I need help!! {2x-4}{2}=11

Mathematics
2 answers:
Morgarella [4.7K]3 years ago
4 0

Answer:

x = 19/4

Step-by-step explanation:

(2x - 4)(2) = 11

We can rewrite the equation in a more simple form.

2(2x - 4) = 11

Apply distributive property.

4x - 8 = 11

Get 4x alone. To get 4x alone, add 8 to both sides.

4x - 8 + 8 = 11 + 8

4x = 19

Get x alone. To get x alone, divide both sides by 4.

4/4x = 19/4

x = 19/4

I hope this helps! Let me know if I got anything wrong or if you need any more help.

Illusion [34]3 years ago
3 0

Step-by-step explanation:

First, you distribute 2 among 2x and -4. This leaves you with 4x - 8 = 11 because when you distribute, you multiply both numbers inside the parenthesis by the number outside of it. Then, you need to eradicate the 8 on the left of the equal sign, so you add 8 to -8 to make it 0, and add 8 to 11 to make it 19. This leaves you with 4x = 19. Finally, you must divide 4x and 19 by 4, leaving you with x = 4.75 or 4¾.

1. (2x - 4)(2) = 11

2. 4x - 8 = 11

3. 4x - 8 + 8 = 11 + 8

4. 4x = 19

5. 4x/4 = 19/4

6. x = 4.75 or 4¾

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If there are x teams in a sports​ league, and all the teams play each other​ twice, a total of​ N(x) games are​ played, where ​N
Elena-2011 [213]

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It will cost $700 to play the entire​ schedule.

Step-by-step explanation:

Given : N(x)=x^2-x

To Find :  A softball league has 5 ​teams, each of which play the others twice. If the league pays ​$35 per​ game, how much will it cost to play the entire​ schedule?

Solution:

Equation for total no. of games when all the teams play each other​ twice is N(x)=x^2-x

Now we are given that A softball league has 5 ​teams, each of which play the others twice.

So, Substitute x = 5 in the given equation

N(x)=5^2-5

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3 years ago
Many manufacturers have quality control programs that include inspection of incoming materials for defects. Suppose a computer m
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Answer:

a) (1,2), (1,3), (1,4), (1,5), (2,3), (2,4),(2,5),(3,4), (3,5) and (4,5)

b)

PX(0) = 0.3

PX(1) = 0.6

PX(2) = 0.1

c)

  • F(x) = 0 if x<0
  • F(x) = 0.3 if 0 ≤ x < 1
  • F(x) = 0.9 if 1 ≤ x < 2
  • F(x) = 1 if x ≥2

Step-by-step explanation:

Lets call the boards 1,2,3,4 and 5

a) There are {5 \choose 2} = 10 possible outcomes: (1,2), (1,3), (1,4), (1,5), (2,3), (2,4),(2,5),(3,4), (3,5) and (4,5).

b) X is 0 if the selected boards doesnt contain 1 or 2. There are {3 \choose 2} = 3 possibilities for this, in concrete, (3,4), (3,5) and (4,5).

PX(0) = 3/10 = 0.3

There is only 1 possibility so that X = 2, which is (1,2), therefore

PX(2) = 1/10 = 0.1

In any other case (there are 6 remaining), X will be equal to 1, so

PX(1) = 6/10 = 0.6

Therefore, X has the following distribution

PX(0) = 0.3

PX(1) = 0.6

PX(2) = 0.1

c) F(0) = 0.3

F(1) = 0.3+0.6 = 0.9

F(2) = 1

We have, as a consequence

  • F(x) = 0 if x<0
  • F(x) = 0.3 if 0 ≤ x < 1
  • F(x) = 0.9 if 1 ≤ x < 2
  • F(x) = 1 if x ≥2

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