Electrical energy !! i hope this helped :))
Compound= many parts together therefore bike is the answer
Answer:
6.02 x 10²⁰ molecules
Explanation:
Given parameters:
Volume of nitrogen = 120cm³
Unknown:
Mass of Nitrogen = ?
Number of molecules present in it = ?
Solution:
At STP;
1 mole of a substance contains 22.4dm³ particles
100cm³ = 1dm³
24cm³ will give 0.024dm³
22.4dm³ of particles are in 1 mole of substances at STP
0.024dm³ of particles will contain = 0.001mole
Mass of Nitrogen = Number of moles x molar mass
molar mass of nitrogen = 14g/mol
Mass of nitrogen = 0.001 x 14 = 0.014g
Number of molecules present;
1 mole of a substance contains 6.02 x 10²³ molecules
0.001 mole of Nitrogen will contain 0.001 x 6.02 x 10²³ = 6.02 x 10²⁰
6.02 x 10²⁰ molecules
Atomic number 70
weight 173
number of neutron = weight - Atomic number
= 173 -70
=103
<span>Since we're going to need to calculate molar masses, let's start with looking up the atomic weights of the associated elements.
Atomic weight carbon = 12.0107
Atomic weight nitrogen = 14.0067
Atomic weight hydrogen = 1.00794
Atomic weight oxygen = 15.999
Molar mass H2O = 2 * 1.00794 + 15.999 = 18.01488 g/mol
Molar mass N2 = 2 * 14.0067 = 28.0134 g/mol
Now calculate the number of moles of H2O and N2 we have
Moles H2O = 6.63 g / 18.01488 g/mol = 0.368029096 moles
Moles N2 = 1.46 g / 28.0134 g/mol = 0.052117915 moles
Since there's 2 hydrogen atoms per H2O molecule, we have
2 * 0.368029096 mol = 0.736058192 moles
of hydrogen.
The mass of that hydrogen is
0.736058192 mol * 1.00794 g/mol = 0.741902494 g
Since there's 2 nitrogen atoms per N2 molecule, we have
2 * 0.052117915 mol = 0.10423583 moles
We already know the mass of nitrogen we have.
Now we need to determine the mass of carbon we have and the number of moles of carbon.
Subtract the know mass of hydrogen and nitrogen from the total mass of Aniline. So
9.71 g - 0.741902494 g - 1.46 g = 7.508097506 g
Moles carbon = 7.508097506 g / 12.0107 g/mol = 0.625117396 mol
We now have the ratio of carbon : hydrogen : nitrogen of
0.625117396 : 0.736058192 : 0.10423583
We need to get a ratio of small integers that closely approximates the above ratio. Start by dividing all the numbers by the smallest of the numbers. Giving:
5.997145089 : 7.061470053 : 1
All three of those values are acceptably close to integers with the ratio of
6:7:1
So the empirical formula of Aniline is C6H7N</span>