Answer:
The correct answer is;
5. They were packaged at a higher pressure on the ground, thus causing the gas inside the packages to expand in the sky where the jet is at a lower pressure.
Explanation:
According to Boyle's law, the pressure of a given mass of gas is inversely proportional to it volume at constant temperature
P₁·V₁ = P₂·V₂
At the factories, the peanuts are packaged at atmospheric conditions whereby P₁ = 1 atm, however, the pressure of the air in the atmosphere decreases with altitude as such the pressure in the airplane jet is about a fraction of hat on the ground by about a factor of 0.7.
Therefore P₂ = 0.7 atm and we have
V₂ = P₁·V₁/P₂ = 1 atm×V₁/0.7 atm = 1.43·V₁
The volume increases at high altitudes
The decomposition reaction for hydrogen peroxide is given below:
2
→ 2 O +
This is a decomposition reaction.
Reactions in which a reactant breaks into two or more products are known as Decomposition reactions.
AB → A + B
here, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction
The decomposition reaction of decomposing hydrogen peroxide is exothermic. When the hydrogen peroxide undergoes a decomposition reaction, heat is also released along with water and oxygen.
Hence the reaction for decomposing hydrogen peroxide is :
2 → 2 O +
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Answer:
a single-replacement reaction replaces one element for another in a compound. A double-replacement reaction exchanges the cations, or the anions, of two ionic compounds.
Answer: The correct answer is option (D)
Explanation:
These aurora are also known as polar lights or northern lights( north poles) or southern lights(south pole) . This is caused by the interaction between the charged particles from the sun with particles present in the upper atmosphere of the earth's atmosphere. The layer in which these interaction takes place is Thermosphere (with high temperature).
Hence, the correct answer is option (D).
Answer:
ΔG=ΔG0+RTlnQ where Q is the ratio of concentrations (or activities) of the products divided by the reactants. Under standard conditions Q=1 and ΔG=ΔG0 . Under equilibrium conditions, Q=K and ΔG=0 so ΔG0=−RTlnK . Then calculate the ΔH and ΔS for the reaction and the rest of the procedure is unchanged.
Explanation:
