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3 years ago

8

Why is it not advisable to touch a canvas tent from inside when it is raining?

1 answer:

Sauron [17]3 years ago

3 0

Answer: When you touch wet canvas, surface tension will draw water to your finger. However, the drop left behind where you touched, like any irregular point on an overhead surface, will draw condensation from inside the tent if it is humid.

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_______ physics cannot account for blackbody radiation.

uysha [10]

Astrophysics is the answer

4 0

3 years ago

Read 2 more answers

Do you think that the universe has a starting point and ending point? explain.

Eddi Din [679]

Answer:

No

Explanation:

I don't think the universe has a starting and ending point because the universe is vast and has not been fully discovered. I think that the universe is endless because all of the stars, planets, and galaxy's have yet to be found and the end or start of the universe is also yet to be discovered so I think that the universe could go on forever.

3 0

3 years ago

What is the electric potential difference of 5cm from a point charge of -2.0µc

vodka [1.7K]

Answer:

V = 360 kV

Explanation:

Given that,

Charge, q = -2µC

We need to find the electric potential difference of 5cm from a point charge.

We know that the formula for the electric potential is given by :

$V=\dfrac{kq}{r}\\\\V=\dfrac{9\times 10^9\times 2\times 10^{-6}}{0.05}\\\\V=360000\ V$

or

$V=360\ kV$

So, the electric potential difference is 360 kV.

7 0

3 years ago

A 40 N crate rests on a rough horizontal floor. A 12 N horizontal force is then applied to it. If the coecients of friction are

bixtya [17]

Answer:

Fr = 20 (N)

Explanation: See atached file ( free body diagram)

As for Newton´s low

∑ Fy = 0

-mg + N = 0 ⇒ - 40 + N = 0 ⇒ N = 40 [Newtons]

by definition : Fr = μs * N ⇒ Fr = 0,5 * 40 ⇒ Fr = 20 (N)

∑ Fx = 0 body is at rest

Fe - Fr = 0

Fr > Fe

Fr > 12 (N) the body is at rest

6 0

3 years ago

German physicist Werner Heisenberg related the uncertainty of an object's position ( Δ x ) to the uncertainty in its velocity (

Ierofanga [76]

Answer:

The uncertainty in the position of the electron is $5.79x10^{-9}m$

Explanation:

The Heisenberg uncertainty principle is defined as:

$\Lambda p\Lambda x$ ≥ $\frac{h}{4 \pi}$ (1)

Where $\Lambda p$ is the uncertainty in momentum, $\Lambda x$ is the uncertainty in position and h is the Planck's constant.

The momentum is defined as:

$p =mv$ (2)

Therefore, equation 2 can be replaced in equation 1

$\Lambda (mv) \Lambda x$ ≥ $\frac{h}{4 \pi}$

Since, the mass of the electron is constant, v will be the one with an associated uncertainty.

$m \Lambda v \Lambda x$ ≥ $\frac{h}{4 \pi}$ (3)

Then, $\Lambda x$ can be isolated from equation 3

$\Lambda x$ ≥ $\frac{h}{m \Lambda v 4 \pi}$ (4)

$\Lambda x = \frac{6.626x10^{-34}J.s}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) 4 \pi}$

But $1J = Kg.m^{2}/s^{2}$

$\Lambda x = \frac{(6.624x10^{-34} Kg.m^{2}/s^{2}.s)}{(9.11x10^{-31} kg)(0.01x10^{6}m/s) (4 \pi)}$

$\Lambda x = 5.79x10^{-9}m$

Hence, the uncertainty in the position of the electron is $5.79x10^{-9}m$

7 0

3 years ago