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spayn [35]
3 years ago
12

ASAP pls answer right and I will mark brainiest

Physics
1 answer:
frozen [14]3 years ago
6 0

Answer: question one: i cannot tell      Question 2: waxing crescent        Question 3:  waxing gibbous     Question 4:    B

Explanation

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A 25-cm rod moves at 5. 0 m/s in a plane perpendicular to a magnetic field of strength 0. 25 t. the rod, velocity vector, and ma
Bad White [126]

Length L = 25 cm = 0.25 m,  B = 600 G =  0.06 T ( 1G = 0.0001 T)

emf= 10 V

Solution:

emf = vBL

v= emf / BL

5 = emf/ (0.25 T× 0.25 m)

emf = 0.3125 v

Magnetic field

The magnetic influence on moving electric charges, electric currents, and magnetic materials is described by a magnetic field, which is a vector field. A force perpendicular to the charge's own velocity and the magnetic field acts on it when the charge is travelling through a magnetic field.

To learn more about the magnetic field refer here:

brainly.com/question/23096032

#SPJ4

5 0
1 year ago
A circular loop of wire with a diameter of 0.626 m is rotated in a uniform electric field to a position where the electric flux
Mila [183]

Answer:

C) 2.44 × 106 N/C

Explanation:

The electric flux through a circular loop of wire is given by

\Phi = EA cos \theta

where

E is the electric field

A is the cross-sectional area

\theta is the angle between the direction of the electric field and the normal to A

The flux is maximum when \theta=0^{\circ}, so we are in this situation and therefore cos \theta =1, so we can write

\Phi = EA

Here we have:

\Phi = 7.50\cdot 10^5 N/m^2 C is the flux

d = 0.626 m is the diameter of the coil, so the radius is

r = 0.313 m

and so the area is

A=\pi r^2 = \pi (0.313 m)^2=0.308 m^2

And so, we can find the magnitude of the electric field:

E=\frac{\Phi}{A}=\frac{7.50\cdot 10^5 Nm^2/C}{0.308 m^2}=2.44\cdot 10^6 N/C

3 0
3 years ago
Si uno de los valores de la tabla no se visualiza en el gráfico, ¿Cómo lo encontramos?
ivanzaharov [21]
No, no me habla espanol. yo soy ingles
6 0
2 years ago
Two 2.0 cm * 2.0 cm metal electrodes are spaced 1.0 mm apart and connected by wires to the terminals of a 9.0 V battery. a. What
NARA [144]

Answer: a) 31.86 *10^-12 C=31.86 pC; b) 18 V

Explanation: In order to explain this problem we have to consider the expression a parallel plates capacitor,which is given by:

C=Q/V where C is equal to C=εo*A/d where A and D are the area and the separation between the plates.

also we have

Q=C*V=ε(o*A/d)*V=(8.85*10^-12*0.02*0.02/1*10^-3)*9=31.86*10^-12 C=31.86pC

Then if the plates apart to a new spacing of 2.0 mm the new capacitance is equal

Cnew=εo*A/2*d so Cnew =Cinitial/2

then Cnew =Q/Vnew (Q is constant after disconnection to the battery)

Finally Vnew= Q/(Cinitial/2)= 2*(Q/Cinitial)= 2*Vinitial= 2*9=18V

5 0
3 years ago
Why is Dimension important in Physics?​
USPshnik [31]

Explanation:

Dimensions help understand how physical amounts are related to their dependence on basic or fundamental volumes, i.e. how the body's dimensions rely on mass, time, length and temperature.

3 0
2 years ago
Read 2 more answers
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