Answer:
a) F = 21.16 N, b) a = 3.17 10²⁸ m / s
Explanation:
a) The outside between the alpha particles is the electric force, given by Coulomb's law
F = 
in that case the two charges are of equal magnitude
q₁ = q₂ = 2q
let's calculate
F = 
F = 21.16 N
this force is repulsive because the charges are of the same sign
b) what is the initial acceleration
F = ma
a = F / m
a = 
21.16 / 4.0025 1.67 10-27
a = 3.17 10²⁸ m / s
this acceleration is in the direction of moving away the alpha particles
Answer:
I think it might be 9 hz but not 100% shore though
Explanation:
Answer:
v = 2.974
Explanation:
Perhaps the formula should be
v = √(2*g*d (sin(θ) - uk*cos(θ) ) This is a bit easier to read.
v = √(2* 9.80*0.725(0.707 - 0.12*0.707) ) Substitute values. Find 2*g*d
v = √14.21 * (0.707 - 0.0849) Figure out Sin(θ) - uk cos(θ)
v = √14.21 * (0.6222)
v = √8.8422 Take the square root of the value
v = 2.974
I think th<span>e upward acceleration of the rocket during the burn phase is 7.</span>8 m/s2
Answer:
The work done is 
Explanation:
Work is defined as the product of force and distance moved in the direction of application of force.
Given Data
distance S= 230m
force F= 140 N
Mass of car m= 1140 kg
Applying the formula for work done we have
The work done by pushing the car for a distance of 
is
