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IrinaK [193]
3 years ago
7

An excited atom decays to its ground state and emits a photon of green light. If instead the atom decays to an intermediate stat

e, then the light emitted could be
Physics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

the light emitting must be of greater wavelength

Explanation:

For this exercise we must use the Planck equation

             E = h f

And the speed of light

            c = λ f

            f = c / λ

We replace

            E = h c / λ

The wavelength of the green light is of the order of 500 nm, let's calculate the energy

          E = 6.63 10⁻³⁴  3 10⁸ /λ

          E = 1,989 10⁻²⁵ /λ

          λ = 500 nm = 500 10⁻⁹ m

          E = 1,989 10⁻²⁵ / 500 10⁻⁹

          E = 3,978 10⁻¹⁹ J

That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy

            E_{int} = E / 2

             E_{int} = 3,978 10⁻¹⁹ / 2 = 1,989 10⁻¹⁹

Let's clear and calculate

           λ = h c / E

           λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹

           λ = 1 10⁻⁶ m

Let's reduce to nm

          λ = 1000 nm

This wavelength is in the infrared region

the light emitting must be of greater wavelength

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Complete Question:

Two objects, T and B, have identical size and shape and have uniform density. They are carefully placed in a container filled with a liquid. Both objects float in equilibrium. Less of object T is submerged than of object B, which floats, fully submerged, closer to the bottom of the container. Which of the following statements is true?

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Answer:

Object B has a greater density than object T

Explanation:

Any object partially or completely submerged in a liquid, experiments an upward force, equal to the weight of  the volume displaced by the liquid. This force is called the buoyant force, and can be expressed as follows:

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This force must be compared with the weight of the object, which is always downward, and can be expressed as follows:

Fg = ρb* Vb * g

where ρb, is the density of the object, and Vb is the total volume of the object, regardless which portion is submerged.

For object B, as it floats fully submerged, this means that both forces are equal in magnitude:

Fg = Fb⇒ ρb* Vb * g = ρl * Vs*g

As Vb = Vs (the object is fully submerged) this means that ρb =ρl.

For object T, as it floats partially submerged, this means that Fg < Fb:

Fg= ρt* Vt * g < Fb = ρl * Vs*g.

Now, we know that ρb =ρl, so we can replace in the equation above:

ρT* Vt * g < ρb*Vs*g

Simplifying common terms, and replacing Vs by KVt (where K is the fraction of the total volume which is submerged, i.e. K<1), we have:

ρt*Vt < ρb*K*Vt ⇒ ρt / ρb < K < 1 ⇒ ρt < ρb ⇒ ρb > ρt

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Determine the slit width that produces a diffraction pattern with the 2nd dark fringe at 6.2mm from the central fringe. The scre
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Answer:

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