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IrinaK [193]
3 years ago
7

An excited atom decays to its ground state and emits a photon of green light. If instead the atom decays to an intermediate stat

e, then the light emitted could be
Physics
1 answer:
scoundrel [369]3 years ago
8 0

Answer:

the light emitting must be of greater wavelength

Explanation:

For this exercise we must use the Planck equation

             E = h f

And the speed of light

            c = λ f

            f = c / λ

We replace

            E = h c / λ

The wavelength of the green light is of the order of 500 nm, let's calculate the energy

          E = 6.63 10⁻³⁴  3 10⁸ /λ

          E = 1,989 10⁻²⁵ /λ

          λ = 500 nm = 500 10⁻⁹ m

          E = 1,989 10⁻²⁵ / 500 10⁻⁹

          E = 3,978 10⁻¹⁹ J

That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy

            E_{int} = E / 2

             E_{int} = 3,978 10⁻¹⁹ / 2 = 1,989 10⁻¹⁹

Let's clear and calculate

           λ = h c / E

           λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹

           λ = 1 10⁻⁶ m

Let's reduce to nm

          λ = 1000 nm

This wavelength is in the infrared region

the light emitting must be of greater wavelength

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Two sealed 1 l containers full of gas are at room temperature. Container a has a pressure of 4 atm and container b has a pressur
loris [4]

Answer:

The number density of the gas in container A is twice the number density of the gas in container B.

Explanation:

Here we have

P·V =n·R·T

n = P·V/(RT)

Therefore since V₁ = V₂ and T₁ = T₂

n₁ = P₁V₁/(RT₁)

n₂ = P₂V₂/(RT₂)

P₁ = 4 atm

P₂ = 2 atm

n₁ = 4V₁/(RT₁)

n₂ =2·V₁/(RT₁)

∴ n₁ = 2 × n₂

Therefore, the number of moles in container A is two times that in container B and the number density of the gas in container A is two times the number density in container B.

This can be shown based on the fact that the pressure  of the container is due to the collision of the gas molecules on the walls of the container, with a kinetic energy that is dependent on temperature and mass, and since the temperature is constant, then the mass of container B is twice that of A and therefore, the number density of container A is twice that of B.

5 0
3 years ago
How to use unbalanced forces in a sentence
leva [86]
Forces occur in pairs and can be either balanced or unbalanced. Balanced forces do not cause a change in motion. Unbalanced Forces do cause a change in motion. 
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3 years ago
A proton and an electron are released from rest in the center of a capacitor.
Sunny_sXe [5.5K]

Answer:

a)  equal 1, b) less than 1

Explanation:

a) the electric force is given by

         Fe = q E

The charge of the electron and proton has the same value, that of the proton is positive and that of the electron is negative

Proton

        Fp = qE

Electron

         Fe = - q E

         Fp / Fe = -1

If we do not take into account the sign the relationship is equal to one (1)

b) to calculate the force we use Newton's second law

           F = ma

           qE = m a

           a = q E / m

The mass of the proton much greater than the mass of the electron

          ap = q E / m_{p}

          ae = - q E /  m_{e}

          ap / ae =  m_{e} /  m_{p} =  m_{e}/1600  m_{e} =1/1600

 It is much smaller than 1

7 0
3 years ago
Rita throws a ball straight up into the air and catches it at the
Kaylis [27]

(1) The potential energy at the top of the ball’s motion is 18 J.

(3) The kinetic energy increases as the potential energy decreases.

(4) The kinetic energy decreases as the potential energy increases.

(5) The total mechanical energy of the ball stays constant.

Explanation:

The total mechanical energy of the ball is equal to the sum of its kinetic energy (K, energy due to the motion) and its potential energy (U, energy due to the height of the ball). Mathematically:

E=K+U

In absence of friction, the mechanical energy of the ball is conserved, so in this case, it is always equal to 18 J. Let's now use this information to analyze each of the given statements:

(1) The potential energy at the top of the ball’s motion is 18 J.  --> TRUE. In fact, at the top, the ball's speed becomes zero, so its kinetic energy is zero: K = 0. This means that all the mechanical energy of the ball is potential energy, therefore

E = U = 18 J

(2) The kinetic energy is less when the ball is thrown than when it is caught.   --> FALSE. As we said, in absence of friction, the mechanical energy is conserved, therefore it always remains equal to 18 J.

(3) The kinetic energy increases as the potential energy decreases.  --> TRUE. As we said, the sum of potential+kinetic energy remains constant:

E = K + U = 18 J

therefore, when the potential energy decreases, the kinetic energy increases.

(4)The kinetic energy decreases as the potential energy increases.  --> TRUE. For the same reason described in (3).

(5)The total mechanical energy of the ball stays constant.  --> TRUE. As we said at the beginning, the total mechanical energy is constant.

(6) The mechanical energy decreases as the ball moves up and increases as the ball comes down. --> FALSE. As we said, the mechanical energy remains constant, so it cannot change.

Learn more about kinetic and potential energy:

brainly.com/question/6536722

brainly.com/question/1198647

brainly.com/question/10770261

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