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Shalnov [3]
3 years ago
10

When iron is exposed to oxygen it rusts or oxidizes. Which of these represents the balanced equation for this chemical change?

Physics
2 answers:
aev [14]3 years ago
5 0
Ur answer is D)!! i just took the test 2 lol

ELEN [110]3 years ago
3 0
<span>I think D) 4Fe + 3O2 → 2Fe2O3 is correct.</span>
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What is a good hypothesis when putting pop rocks into soda?
8_murik_8 [283]
That it will erupt upon contact. Hope it helps!
6 0
3 years ago
A piston releases 18 J of heat into its surroundings while expanding from 0.0002 m^3 to 0.0006 m^3 at a constant pressure of 1.0
Elodia [21]

Answer:

value of heat is 18 J

2. step by step

formular w=p(volume1-volume2)

w= 1.0×10^5(0.0006-0.0004)

w= 40 J

8 0
3 years ago
Uma partícula com carga “Q”, no vácuo, gera um potencial elétrico de 600 volts a uma distância de 6,0 m, determine o valor dessa
garik1379 [7]

Answer:

q =  400 nC

the correct answer is b

Explanation:

The expression for the electric potential of a point charge is

            V = k q / r

they ask us for the electrical charge

          q = V r / k

let's calculate

         Q = 600 6.0 / 9 10⁹

         Q = 4 10⁻⁷ C

let's reduce to nC

          Q = 4 10⁻⁷ C (10⁹ nC / 1C)

          q = 4 10² nC = 400 nC

the correct answer is b

Traslate

La expresión para el potencial eléctrico de una carga puntual es

            V = k q/r

nos piden la carga eléctrica

          q= V r /k

          calculemos

         Q= 600  6,0 / 9 10⁹

         Q=  4 10⁻⁷ C

reduzcamos a nC

          Q = 4 10⁻⁷ C(10⁹ nC/1C )  

          q = 4 10² nC = 400 nC

la respuesta correcta es b

8 0
3 years ago
As people try to rid fruit, vegetables, and ornamentals from bugs, our environment and many of its inhabitants are harmed. The p
xeze [42]

Answer:

Systemic pesticides

Explanation:

4 0
3 years ago
The highest speed of a cheetah is 100 km/hr and the highest speed of a gazelle is 80 km/hr. If at t = 0 both animals are running
Tju [1.3M]

Answer:

t=18s

Explanation:

The final position of an object moving at constant speed is given by the formula x=x_0+vt, where x_0 is its initial position, v its speed and t the time elapsed.

For the cheetah we have x_c=x_{0c}+v_ct, and for the gazelle x_g=x_{0g}+v_gt. We want to know at which t their positions are equal, that is, x_c=x_g, which means,

x_{0c}+v_ct=x_{0g}+v_gt

Where we can do:

v_ct-v_gt=x_{0g}-x_{0c}

(v_c-v_g)t=x_{0g}-x_{0c}

t=\frac{x_{0g}-x_{0c}}{v_c-v_g}

We then substitute the values we have (the initial position of the cheetah is 0m), writing the meters in km so distance units cancel out correctly:

t=\frac{0.1km-0km}{100km/hr-80km/hr}=0.005hr=18s

On the last step we just multiply by 3600 because is the number of seconds in an hour.

3 0
3 years ago
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