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natita [175]
3 years ago
15

ABC ∆ where Angle A =90° , AB = 12 m, AC = 9 m . Find BC ?

Mathematics
1 answer:
Setler [38]3 years ago
6 0

Answer:

15m

Step-by-step explanation:

Use Pythagoras

Folow the steps in the image

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9.
Svet_ta [14]

Answer:

√234

Step-by-step explanation:

Drawing it out will help you

3 0
3 years ago
Item 3 RectangleABCD has vertices A(1, 2), B(4, 2), C(1, −2), and D(4, −2). A dilation with a scale factor of 6 and centered at
tigry1 [53]

Answer:

B

Step-by-step explanation:

I'm pretty sure its b because its ratio matches the (4,2)

5 0
3 years ago
Read 2 more answers
If 75% of a number is 165 and 10% of the same number is 22, find 85% of that number.
omeli [17]

Answer: Hi there! 187 would be your answer.

Step-by-step explanation:

7 0
3 years ago
Multiply: <br> <img src="https://tex.z-dn.net/?f=%5Cfrac%7B8n%5E%7B2%7D%20%7D%7Bm%5E%7B2%7D-16%20%7D" id="TexFormula1" title="\f
Mkey [24]

9514 1404 393

Answer:

  4mn/(3m+12)

Step-by-step explanation:

It is often helpful to factor expressions so that common factors can cancel.

  \dfrac{8n^2}{m^2-16}\times\dfrac{m^2-4m}{6n}=\dfrac{8mn^2(m-4)}{6n(m-4)(m+4)}=\dfrac{4mn}{3(m+4)}\\\\=\boxed{\dfrac{4mn}{3m+12}}

3 0
3 years ago
Find domain of y=rad20-6x
Evgesh-ka [11]
Domain, on an "even root" context, means, an even root cannot have a negative radicand, since  say for example \bf \sqrt{-25}\ne -5\qquad why?\implies (-5)(-5)=25

so... you end up with an "imaginary value"

so... for the case of 20-6x
"x", the domain, or INPUT
can afford to have any value, so long it doesn't make the radicand negative

to check for that, let us make the expression to 0, and see what is "x" then

\bf 20-6x=0\implies 20=6x\implies \cfrac{20}{6}=x\implies \cfrac{10}{3}=x

now, if "x" is 10/3, let's see \bf \sqrt{20-6\left( \frac{10}{3} \right)}\implies \sqrt{20-20}\implies \sqrt{0}\implies 0

now, 0 is not negative, so the radicand is golden

BUT, if "x" has a value higher than 10/3, the radicand turns negative
for example  \bf x=\frac{11}{3}&#10;\\\\\\&#10;&#10;\sqrt{20-6\left( \frac{11}{3} \right)}\implies \sqrt{20-22}\implies \sqrt{-2}

so.. that's not a good value for "x"

thus, the domain, or values "x" can safely take on, are all real numbers from 10/3 onwards, or to infinity if you wish
5 0
3 years ago
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