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Mekhanik [1.2K]
2 years ago
7

What types of atoms will experience radioactivity?

Chemistry
1 answer:
Otrada [13]2 years ago
3 0

Answer:

Alpha particles, Beta particles, Gamma rays

Alpha Is the least harmful

Beta is second most harmful

Gamma is most dangerous

Explanation:

You might be interested in
Describe why an element's physical properties are different from its chemical properties. Include in your answer an example of o
Contact [7]

Answer:

Explanation:

Hello,

At first, they differ because a physical property is observed without changing the nature of the substance. On the other hand, a change in the nature of the substance must be carried out to observe a chemical property.

As examples, density, solubility and odor (physical properties) could be known by just analyzing a substance, nonetheless, pH, reactivity or combustibility must be known by submitting the substance to a specific chemical reaction.

Best regards.

4 0
3 years ago
What is the density of an object with a mass of 40.0 g and a volume of 80.0 cm3
Komok [63]
Density = mass/volume
D  = 40/80 = 0.5g
D= 0.5g
8 0
3 years ago
Silver occurs in trace amounts in some ores of lead, and lead can displace silver from solution: Pb(s) + 2Ag+ (aq) LaTeX: \longr
VikaD [51]

Answer : The value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

Explanation :

The balanced cell reaction will be,

Pb(s)+2Ag^+(aq)\rightarrow Pb^{2+}(aq)+2Ag(g)

The half-cell reactions are:

Oxidation reaction (anode) : Pb(s)\rightarrow Pb^{2+}(aq)+2e^-

Reduction reaction (cathode) : 2Ag^+(aq)+2e^-\rightarrow 2Ag(g)

Relationship between standard Gibbs free energy and standard electrode potential follows:

\Delta G^o=-nFE^o_{cell}

where,

\Delta G^o = standard Gibbs free energy

F = Faraday constant = 96500 C

n = number of electrons in oxidation-reduction reaction = 2

E^o_{cell} = standard electrode potential of the cell = 0.93 V

Now put all the given values in the above formula, we get:

\Delta G^o=-2\times 96500\times 0.93

\Delta G^o=-179490J/mol=-179.49kJ/mol\approx -180kJ/mol

Now we have to calculate the value of 'K'.

\Delta G^o=-RT\ln K

where,

\Delta G_^o =  standard Gibbs free energy  = -180 kJ/mol

R = gas constant = 8.314\times 10^{-3}kJ/mole.K

T = temperature = 298 K

K = equilibrium constant = ?

Now put all the given values in the above formula 1, we get:

-180kJ/mol=-(8.314\times 10^{-3}kJ/mole.K)\times (298K)\times \ln K

K=3.6\times 10^{31}

Therefore, the value of \Delta G^o and K is, -180 kJ/mol and 3.6\times 10^{31}

5 0
3 years ago
An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons. What is the name of this element?
DedPeter [7]

Given :

An atom of a certain element has 12 protons, 14 neutrons, and 2 valence electrons.

To Find :

The name of this element.

Solution :

We know, element with atomic number ( number of protons ) 12 and valance electrons is Magnesium.

Now, isotope of magnesium of proton with 14 neutrons is Mg-16 .

Therefore, name of element is Mg-16 .

Hence, this is the required solution.

5 0
2 years ago
When the compound BaCl2 forms , what happens to the Ba and Cl ions
Korvikt [17]
Ba stays as Ba+2 and Cl stays as Cl-
6 0
3 years ago
Read 2 more answers
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