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Hunter-Best [27]
2 years ago
5

In the water cycle, clouds form as a result of _____?

Chemistry
1 answer:
Anika [276]2 years ago
8 0

Answer:

In water cycle clouds form as a result of water vapours

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Help me out with these three formulas
ddd [48]
Carbon dioxide it should be water oxygen
7 0
3 years ago
or a particular isomer of C 8 H 18 , the combustion reaction produces 5104.1 kJ of heat per mole of C 8 H 18 ( g ) consumed, und
beks73 [17]

Answer:

The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

Explanation:

The given chemical reaction is as follows.

C_{8}H_{18}(g)+ \frac{25}{2}O_{2}(g) \rightarrow 8CO_{2}(g)+9H_{2}O(g)

\Delta H^{o}_{rxn}= -5104.1kJ/mol

The expression for the entropy change for the reaction is as follows.

\Delta H^{o}_{rxn}=[8\Delta H^{o}_{f}(CO_{2}) +9\Delta H^{o}_{f}(H_{2}O)]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}\Delta H^{o}_{f}(O_{2})]

\Delta H^{o}_{f}(H_{2}O)= -241.8kJ/mol

\Delta H^{o}_{f}(CO_{2})= -393.5kJ/mol

\Delta H^{o}_{f}(O_{2})= 0kJ/mol

Substitute the all values in the entropy change expression.

-5104.1kJ/mol=[8(-393.5)+9(-241.8)kJ/mol]-[\Delta H^{o}_{f}(C_{8}H_{18})+ \frac{25}{2}(0)kJ/mol]

-5104.1kJ/mol=-5324.2kJ/mol -\Delta H^{o}_{f}(C_{8}H_{18})

\Delta H^{o}_{f}(C_{8}H_{18}) =-5324.2kJ/mol +5104.1kJ/mol

=-220.1kJ/mol

Therefore, The standard enthalpy of formation of this isomer of C_{8}H_{18} is -220.1 kJ/mol.

4 0
3 years ago
Which statement accurately describes the charge of the nucleus of an atom? A. The nucleus can be either positively charged or ne
BARSIC [14]
<span>A. The nucleus can be either positively charged or neutral.

The nucleus is located at the center of an atom wherein it contains the protons and the neutrons.</span>
3 0
3 years ago
Read 2 more answers
Is water used to test cheese for protein
nekit [7.7K]

Answer:

yes

Explanation:

because it help the body hydrate

7 0
2 years ago
How many moles of CO2 must dissolve in excess water to produce 12 moles of<br><br> H2CO3?
vodka [1.7K]

Answer:

12 moles of CO₂.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CO₂ + H₂O —> H₂CO₃

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Finally, we shall determine the number of moles of CO₂ that will dissolve in water to produce 12 moles of H₂CO₃. This can be obtained as follow:

From the balanced equation above,

1 mole of CO₂ dissolves in water to produce 1 mole of H₂CO₃.

Therefore, 12 moles of CO₂ will also dissolve in water to produce 12 moles of H₂CO₃.

Thus, 12 moles of CO₂ is required.

3 0
3 years ago
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