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sergij07 [2.7K]
3 years ago
11

Describe the motion of molecules in an ice cube and in a radiator in winter

Chemistry
2 answers:
KIM [24]3 years ago
8 0
The motion of molecules in a ice cube are so packed together that they can't move freely like molecules in liquids and gases
kiruha [24]3 years ago
7 0

Molecules in an ice cube have lower kinetic energy than molecules in a radiator.

Molecules in an ice cube move more slowly than molecules in a radiator. They collide with less force than molecules in a radiator.

When in direct contact, the fast-moving molecules in the radiator collide with the slow-moving molecules in the ice cube.

Kinetic energy is transferred from the molecules in the radiator to the molecules in the ice cube, causing a slowdown of the radiator molecules and an acceleration of the ice molecules.

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d=m/v
m=v*d
=78.3*2.7
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ΔG o for the reaction H2(g) + I2(g) ⇌ 2HI(g) is 2.60 kJ/mol at 25°C. Calculate ΔG o , and predict the direction in which the rea
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Answer:

The reaction is not spontaneous in the forward direction, but in the reverse direction.

Explanation:

<u>Step 1: </u>Data given

H2(g) + I2(g) ⇌ 2HI(g)     ΔG° = 2.60 kJ/mol

Temperature = 25°C = 25+273 = 298 Kelvin

The initial pressures are:

pH2 = 3.10 atm

pI2 = 1.5 atm

pHI 1.75 atm

<u>Step 2</u>: Calculate ΔG

ΔG = ΔG° + RTln Q  

with ΔG° = 2.60 kJ/mol

with R = 8.3145 J/K*mol

with T = 298 Kelvin

Q = the reaction quotient → has the same expression as equilibrium constant → in this case Kp = [p(HI)]²/ [p(H2)] [p(I2)]

with pH2 = 3.10 atm

pI2 = 1.5 atm

pHI 1.75 atm

Q = (3.10²)/(1.5*1.75)

Q = 3.661

ΔG = ΔG° + RTln Q  

ΔG = 2600 J/mol + 8.3145 J/K*mol * 298 K * ln(3.661)  

ΔG =5815.43 J/mol = 5.815 kJ/mol

To be spontaneous, ΔG should be <0.

ΔG >>0 so the reaction is not spontaneous in the forward direction, but in the reverse direction.

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BECAUSE IT NEVER BREAKES


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