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iren [92.7K]
3 years ago
8

What are units of molarity

Chemistry
1 answer:
liberstina [14]3 years ago
4 0

Answer:The units of molarity are M or mol/L. A 1 M solution is said to be “one molar.”

Explanation:

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Hello can you please help me to solve above fill in the blank questions ​
LiRa [457]

Answer:

C2H5OH is a formula of ethyl alchol or ethanol.

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Explanation:

i hope this will help you :)

7 0
3 years ago
Gas laws describe and predict the behavior of gases without attempting to explain why they happen
Nutka1998 [239]

The gas laws describe and predict the behavior of gases with an explanation and experimental data

So the given statement is False.

2) The volume of gas can be calculated based on Avagadro's law

It states that the volume of a gas is directly proportional or varies with the moles of the gas. Higher the moles more the volume, condition is the pressure and temperature are constants in the two conditions

Thus as here the pressure and temperature of nitrogen gas is kept constant

V α  moles

or

\frac{V1}{n1}=\frac{V2}{n2}

Where

V1 = 6 l

n1 = 0.50 mol

V2 = ?

n2 = 0.75 mol

On putting values

V2 = 6 X 0.75 / 0.5 = 9 L

so resulting volume of the gas will be 9L

5 0
3 years ago
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Which of the following statements about the greenhouse effect is false? Greenhouse gases include carbon dioxide, chlorofluorocar
7nadin3 [17]
B is definitely correct
5 0
3 years ago
When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the
Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}

For 1000 C, W = x grams

\tt x=\dfrac{1000.e}{96500}=0.0104e

For 5x grams :

\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C

6 0
3 years ago
1. Calculate the attractive bonding force for NaF and for MgO when the ions just touch. Based on the attractive bonding force, w
Andreas93 [3]

Answer:

The attractive force is negative and MgO has a higher melting point

Explanation:

From Couloumb's law:

Energy of interaction, E = k \frac{q1q2}{r}

where q1 and q2 are the charges of the ions, k is Coulomb's constant and r is the distance between both ions, i.e the atomic radii of the ions.

If you look at Coulomb's law, you note that in the force is negative (because q1 is negative while q2 is positive).

In addition to that, the compounds MgO and NaF have similar combined ionic radii, then we can determine the melting point trend from the amount of energy gotten

The melting point of ionic compounds is determined by 1. charge on the ions 2. size of ions. while NaF has smaller charges (+1 and -1), MgO (+2 and -2) has larger charges and greater combined atomic radii. This implies that the compound with greater force would have a higher melting point.

Hence the compound MgO would have a higher melting point than NaF.

5 0
3 years ago
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