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Molodets [167]
3 years ago
9

Its math and struggling with it

Mathematics
1 answer:
svlad2 [7]3 years ago
8 0

Answer: Solve for m m by simplifying both sides of the equation, then isolating the variable. m=15

Step-by-step explanation: Reducing to lowest terms On both sides

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Solve the equation then check your solution 5p=140 <br> A)28<br> B)700<br> C)-28<br> D)26
Kruka [31]

Answer:

p=28

Step-by-step explanation:

5p=140

To to find the value of p divide both sides by 5 (5p/5 and 140/5)

p=28!


4 0
3 years ago
Read 2 more answers
PLEASEE HELPP IM DESPERATE I’LL GIVE BRAINLIEST TO WHOEVER ANSWERS FIRST CORRECTLY
DedPeter [7]

Answer:

x = 2, -2, -1/5

Step-by-step explanation:

g(x)= 5x^3+x^2-20x-4

g(x)= x^2(5x+1)-4(5x+1)

g(x)=(x^2-4)(5x+1)

g(x)=(x-2)(x+2)(5x+1)

x-2=0

x= 2

x+2=0

x= -2

5x+1=0

x= -1/5

8 0
3 years ago
PLEASE HELP
ipn [44]

Answer: (0,0),(0,4), and (5,0)

Step-by-step explanation:

It is easy to find lengths of horizontal and vertical segments and distances from (0,0) so always place one vertex at the origin and one or more sides on an axis.

This answer has an x intercept and y intercept.

3 0
3 years ago
Evaluate the following expression: 082
Sauron [17]
This for points.





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7 0
3 years ago
Which expression is equivalent to...? Screenshots attached. Please help! Thank you.
Studentka2010 [4]

Answer:

4x^{3} y^{2} (\sqrt[3]{4 x y})

Step-by-step explanation:

Another complex expression, let's simplify it step by step...

We'll start by re-writing 256 as 4^4

\sqrt[3]{256 x^{10} y^{7} } = \sqrt[3]{4^{4} x^{10} y^{7} }

Then we'll extract the 4 from the cubic root.  We will then subtract 3 from the exponent (4) to get to a simple 4 inside, and a 4 outside.

\sqrt[3]{4^{4} x^{10} y^{7} } = 4 \sqrt[3]{4 x^{10} y^{7} }

Now, we have x^10, so if we divide the exponent by the root factor, we get 10/3 = 3 1/3, which means we will extract x^9 that will become x^3 outside and x will remain inside.

4 \sqrt[3]{4 x^{10} y^{7} } = 4x^{3} \sqrt[3]{4 x y^{7} }

For the y's we have y^7 inside the cubic root, that means the true exponent is y^(7/3)... so we can extract y^2 and 1 y will remain inside.

4x^{3} \sqrt[3]{4 x y^{7} } = 4x^{3} y^{2} \sqrt[3]{4 x y}

The answer is then:

4x^{3} y^{2} \sqrt[3]{4 x y} = 4x^{3} y^{2} (\sqrt[3]{4 x y})

4 0
3 years ago
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