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3 years ago

Im lonely im so lonely and boreddddddddddddddddddddddddddddddddddddddddddddddddddddddddddddd

Mathematics

2 answers:

Karolina [17]3 years ago

8 0

Answer:

im so lOoOoOoOoEnLy

Step-by-step explanation:

gregori [183]3 years ago

3 0

Answer:

Okay..

Step-by-step explanation:

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which expression have a value of 16/81? check all that apply. (2/3)^4, (16/3)^4, (4/81)^2, and (4/9)^2

notka56 [123]

$Use\ \left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\\left(\dfrac{2}{3}\right)^4=\dfrac{2^4}{3^4}=\dfrac{16}{81}\ :)\\\\\left(\dfrac{16}{3}\right)^4=\dfrac{16^4}{3^4}=\dfrac{16^4}{81}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{81}\right)^2=\dfrac{4^2}{81^2}=\dfrac{16}{81^2}\neq\dfrac{16}{81}\ :(\\\\\left(\dfrac{4}{9}\right)^2=\dfrac{4^2}{9^2}=\dfrac{16}{81}\ :)$

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4 years ago

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Nahee is running around the circular track with equation x2+y2=10000 at a speed of 2.9 meters per second. She starts at the poin

Nana76 [90]

Answer:

The coordinates are (58.1, - 81.4).

Step-by-step explanation:

The distance traveled by Nahee after 13 minutes at the rate of 2.9 m/sec along the arc of the circle with equation x² + y² = 100², will be (13 × 60 × 2.9) = 2262 m

Now, the perimeter of the circle is 2πr = $2 \times \frac{22}{7}\times 100 = 628.57$ m

Therefore, after traveling three full circles and a half-circle the remaining arc length will be [2262 - (628.57 × 3) - (628.57 ÷ 2)] = 62 m

Therefore, Nahee will finish his run in the fourth quadrant.

Now, the angle made by the arc length of 62 m at the center will be = $\frac{360}{628.57}\times 62 = 35.512^{\circ}$

So, the angle made with positive x-axis will be (90° - 35.521°) = 54.488°

Now, the coordinates of the finishing point are (x,-y) = (rCos 54.488°, - rSin 54.488°) = (58.1, - 81.4) (Answer)

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3 years ago

X7=−0.21 helllllllllllllllllllllllllllppppp

Anastasy [175]

The answer is x= -0.03

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3 years ago

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How many solutions does the following. system of equations have? 6x-3y= -9 y=2x+3. one solution, infinitely many solutions or no

DanielleElmas [232]

Answer:

D on edg

Step-by-step explanation:

7 0

3 years ago

If the vertex of a parabola is (-4, 6) and another point on the curve is (-3, 14), what is the coefficient of the squared expres

Luda [366]

$\bf \qquad \textit{parabola vertex form}\\\\\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array}\qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex\ (-4,6)\qquad 
\begin{cases}
h=-4\\
k=6
\end{cases}\implies y=a(x-(-4))^2+6
\\\\\\
y=a(x+4)^2+6
\\\\\\
\textit{we also know that }
\begin{cases}
x=-3\\
y=14
\end{cases}\implies 14=a(-3+4)^2+6$

solve for "a"

8 0

4 years ago