Answer:
infinitely many
Step-by-step explanation:
Rewrite these equations as
y = (1/2)x + 1
2y = x + 2
and then solve the second for y: y = (1/2)x + 1. Note that these end results are identical. The two lines coincide; that is, one lies right on top of the other. Thus, there are infinitely many solutions.
Answer:
<em>Factored Form: </em><em> </em><em>( y - 2 )( 3y + 7 )</em>
Step-by-step explanation:
<em>1. Let us first write down the problem at hand: </em>3y^2 + y - 14
<em>2. Now let us break this expression into groups: </em>
3y^2 - 6y + 7y - 14 ⇒ ( 3y^2 - 6y )( 7y - 14 )
<em>3. Factor 3y from 3y^2 - 6y:</em>
3y^2 - 6y ⇒ 3y( y - 2 )
<em>4. Factor 7 from 7y - 14:</em>
7y - 14 ⇒ 7( y - 2 )
<em>5. Substitute Step #3, 4 ⇒ Step #2:</em>
3y( y - 2 ) + 7( y - 2 )
<em>6. Factor common term y - 2:</em>
<em>Answer: ( y - 2 )( 3y + 7 )</em>
Answer:
First quartile = 3.5
Third quartile = 6.5
Step-by-step explanation:
Sales for last 20 hours :
3, 4, 5, 5, 6, 7
Using the data given :
The first quartile, Q1 ;
Q1 = 1/4(n+1)th term
n = 6
Q1 = 1/4(6 + 1)th term
Q1 = 7/4 = 1.75 th term
(3 + 4) / 2 = 7/2 = 3.5
The third quartile, Q3:
Q3 = 3/4(n+1)th term
n = 6
Q3 = 3/4(6 + 1)th term
Q3 = 21/4 = 5.25th term
(5th + 6th) term / 2
(6 + 7) / 2 = 13/2 = 6.5
Answer: 
Step-by-step explanation:
You know that Josh's base salary is:
And, according to the information given in the exercise, Josh makes $70 more for every copy he sales.
Knowing this you can determine that his total pay will be the sum of his base salary and the podruct of $70 and the number of copies.
Therefore, if Josh sells 22 copies, then we get that his total pay is:
