Answer:
The distance is 8 cm
Step-by-step explanation:
The chord and the diameter form one leg and the hypotenuse of a right triangle. The other leg, BD, has length ...
BD² +AB² = AD²
BD² = AD² -AB² = 34² -30² = 256
BD = √256 = 16
The segment from the center of the circle to the midpoint of the chord is the midline of triangle ABD, so is half the length of BD.
distance from AB to the center = 16/2 = 8 . . . cm
I think the answer would be c
Just replace a with 4 and b with 2 and your equation looks like
3.14 (4×2+4×2)
solve within the parenthesis first
3.14 (8+8)
3.14 (16) =50.24
We want to solve 9a² = 16a for a.
Because the a is on both sides, a good strategy is to get all the a terms on one side and set it equal to zero. Then we apply the Zero Product Property (if the product is zero then so are its pieces and Factoring.
9a² = 16a
9a² - 16a = 0 <-----subtract 16a from both sides
a (9a - 16) = 0 <-----factor the common a on the left side
a = 0 OR 9a - 16 =0 <----apply Zero Product Property
Since a = 0 is already solved we work on the other equation.
9a - 16 = 0
9a = 16 <----------- add 16 to both sides
a = 16/9 <----------- divide both sides by 9
Thus a = 0 or a = 16/9
You said 2x - 9 < 7
Add 9 to each side: 2x < 16
Divide each side by 2 : x < 8 .
