Answer:
<em>p ≥ 5</em>
<em>Scott will buy at least 5 kilograms of candy.</em>
Step-by-step explanation:
<u>Inequalities</u>
The candy Scott buys cost $7 per kilogram.
Let's set p=number of kilograms of candy Scott will buy.
The money spent to buy p kilograms of candy is 7p dollars.
The condition states he will spend at least $35 on candies, thus the following inequality is formed:
7p ≥ 35
Dividing by 7:
p ≥ 35/7
Operating:
p ≥ 5
Scott will buy at least 5 kilograms of candy.
Answer:
85-86%
Step-by-step explanation:
Make it an equation
You want to find the percent out of a hundred, so 42 is 100 since it is all of the questions and 36 is the unknown percent X
36/42 = X/100
36 X
42 100
Cross multiply
Do math and solve for X
36 x 100 = 42 x X
3600=42X
X=85.71
Answer:

Step-by-step explanation:
since q(x)=-4
substitute
hence
-4=12x-3
take -3 to the other side where it becomes positive
therefore
-1=12x
divide by 12
you will get the above answer
Answer:
0.0032
The complete question as seen in other website:
There are 111 students in a nutrition class. The instructor must choose two students at random Students in a Nutrition Class Nutrition majors Academic Year Freshmen non-Nutrition majors 17 18 Sophomores Juniors 13 Seniors 18 Copy Data. What is the probability that a senior Nutrition major and then a junior Nutrition major are chosen at random? Express your answer as a fraction or a decimal number rounded to four decimal places.
Step-by-step explanation:
Total number of in a nutrition class = 111 students
To determine the probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major, we would find the probability of each of them.
Let the probability of choosing a junior non-Nutrition major = Pr (j non-N)
Pr (j non-N) = (number of junior non-Nutrition major)/(total number students in nutrition class)
There are 13 number of junior non-Nutrition major
Pr (j non-N) = 13/111
Let the probability of choosing a sophomore Nutrition major = Pr (S N-major)
Pr (S N-major)= (number of sophomore Nutrition major)/(total number students in nutrition class)
There are 3 number of sophomore Nutrition major
Pr (S N-major) = 3/111
The probability that the two students chosen at random is a junior non-Nutrition major and then a sophomore Nutrition major = 13/111 × 3/111
= 39/12321
= 0.0032
<span>Consider the remainder of the division of the power exponent of i by 4.
For a remainder r equal to 0, 1, 2 or 3, we have a power equal to 1, i, -1 or -i respectively, therefore:
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Answer:

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