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Romashka-Z-Leto [24]
2 years ago
8

I need help asap plz!!!​

Mathematics
1 answer:
svet-max [94.6K]2 years ago
5 0

Answer:

AC ≈ 10.3

Step-by-step explanation:

Using the tangent ratio in the right triangle

tan48° = \frac{opposite}{adjacent} = \frac{AC}{AB} = \frac{AC}{9.3} ( multiply both sides by 9.3 )

9.3 × tan48° = AC , then

AC ≈ 10.3 ( to 3 sf )

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aliina [53]

Answer:

y intercept is 0,0 Slope is 15 equation is y=15x

6 0
2 years ago
Solve. x - 6 = 3 A) x = -3 B) x = 2 C) x = 3 D) x = 9 Please Help im trying to get my grades up
kirza4 [7]

x=9

Add 6 to both sides of the equation. x = 3 + 6

Add 3and 6.

x=9

6 0
3 years ago
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Is this expression equivalent?<br> 3v+v and 12v over 3
xeze [42]
Yes this is equal because 3v+v is 4v and if you divide 12v by 3 you also get 4v
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3 years ago
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Will give brainlyest if u help
goblinko [34]

Answer:

No, because it fails the vertical line test ⇒ B

Step-by-step explanation:

To check if the graph represents a function or not, use the vertical line test

<em>Vertical line test:</em> <em>Draw a vertical line to cuts the graph in different positions, </em>

  • <em>if the line cuts the graph at just </em><em>one point in all positions</em><em>, then the graph </em><em>represents a function</em>
  • <em>if the line cuts the graph at </em><em>more than one point</em><em> </em><em>in any position</em><em>, then the graph </em><em>does not represent a function </em>

In the given figure

→ Draw vertical line passes through points 2, 6, 7 to cuts the graph

∵ The vertical line at x = 2 cuts the graph at two points

∵ The vertical line at x = 6 cuts the graph at two points

∵ The vertical line at x = 7 cuts the graph at one point

→ That means the vertical line cuts the graph at more than 1 point

   in some positions

∴ The graph does not represent a function because it fails the vertical

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7 0
3 years ago
5#The distribution of scores on a standardized aptitude test is approximately normal with a mean of 480 and a standard deviation
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We want to find the value that makes

P(X\ge x)=0.2

To find it we must look at the standard normal table, using the complementary cumulative table we find that

P(Z\ge z)=0.20045\Leftrightarrow z=0.84

Then, using the z-score we can find the minimum score needed, remember that

z=\frac{x-\mu}{\sigma}

Where

σ = standard deviation

μ = mean

And in our example, x = minimum score needed, therefore

\begin{gathered} 0.84=\frac{x-480}{105} \\  \\ x=0.84\cdot105+480 \\  \\ x=568.2 \end{gathered}

Rounding to the nearest integer the minimum score needed is 568, if you get 568 you are at the top 20.1%.

7 0
1 year ago
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