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Keith_Richards [23]
3 years ago
13

Help pls im slow !!!!!!!!

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0

Answer:

z= 1/3

love ur chrome browser too

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Molly was allowed to trick or treat from 6:30 pm to 8:45pm if she averaged coating 2 houses every 9 minutes during that time how
MissTica

Answer:

30 houses

Step-by-step explanation:

Time from 6:30 pm to 8:45 pm = 2 hr 15 min

Time in minutes = (2 hr × 60 min/hr) + 15 min = 135 min

Average visit = 9 min per 2 houses = 4.5 min per house

Number of visits = 135 min ÷ 4.5 min/house = 30 houses

3 0
3 years ago
The lines below are parallel. If the slope of the green line is -3, what is the
julia-pushkina [17]

Answer:-3

Step-by-step explanation:

The expression is already in decimal form.

−3 slope

8 0
3 years ago
Each month, Terrance spends $128.00 on his car payment, $63.00 for car insurance, and $45.00 on gas. Round each amount to the ne
max2010maxim [7]
The answer is $240.

If you round each amount to the nearest ten you get $130.00, $60.00, and 50.00. When you add all of those together you get an estimated amount of $240.
8 0
3 years ago
What is 17 divided by 2635
Sliva [168]

Answer:0.0064516129

Step-by-step explanation:

8 0
3 years ago
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
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