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BlackZzzverrR [31]
3 years ago
6

A gas in a sealed container has an initial pressure of 125 kPa at 25.0∘C. If the pressure is increased to 150.0 kPa, what will t

he new temperature be?
Chemistry
1 answer:
Serjik [45]3 years ago
5 0

Answer:

T'=30^{\circ} C

Explanation:

Initial pressure, P = 125 kPa

Initial temperature, T = 25.0°C

If new pressure is increased to P' = 150.0 kPa

We need to find new temperature. According to Gay-Lussac's law,

P ∝ T

or

\dfrac{P}{T}=\dfrac{P'}{T'}\\\\T'=\dfrac{P'T}{P}\\\\T'=\dfrac{150\times 25}{125}\\\\=30^{\circ} C

So, the new temperature will be 30^{\circ} C.

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