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Pepsi [2]
3 years ago
12

Jason applies a force of 4.00 newtons to a sled at an angle 62.0 degrees from the ground. What is the component of force effecti

ve in pulling the sled horizontally along the ground?
Physics
1 answer:
creativ13 [48]3 years ago
6 0

Answer:

1.88 N

Explanation:

Given in the question,

force applied by Jason  = 4N

angle which it make with the ground = 62°

The angle made with the x-axis is cosine of the angle 62°

Thus, the horizontal component of the force is equal to

F = 4.00(cos62⁰) = 1.88 N

              /

            /

4N     /

       /

     / 62°

  Ф ------------------------

   

by using trigonometry identity

cosФ = adjacent / hypotenuse

horizontal force = hypotenuse (cos(Ф))

horizontal force = 4cos(62)

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A projectile is launched at an angle of 29 degrees above the horizontal with an initial velocity of 36.6 at an unknown height.
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The vertical velocity of the projectile upon returning to its original is 17. 74 m/s

<h3>How to determine the vertical velocity</h3>

Using the formula:

Vertical velocity component , Vy = V * sin(α)

Where

V = initial velocity = 36. 6 m/s

α = angle of projectile = 29°

Substitute into the formula

Vy = 36. 6 * sin ( 29°)

Vy = 36. 6 * 0. 4848

Vy = 17. 74 m/s

Thus, the vertical velocity of the projectile upon returning to its original is 17. 74 m/s

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1 year ago
How much energy is required to accelerate a golf ball of mass 0.046 kg initially at rest to a speed of 0.75c?
Andrew [12]

The required energy to accelerate the golf ball is  0.232875X10^{16} kg-m/sec^2.

<h2>What is Energy?</h2>
  • Energy, which is observable in the execution of labor as well as in the form of light and heat, is the quantitative quality that is transmitted to an object or to a physical phenomenon in physics.
  • Energy is a preserved resource; according to the rule of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.
  • The joule, which is defined as "the energy transmitted to an object by the effort of moving it a length of one metre against a force of one newton," is the standard measure for power in the International System of Units (SI).

Given that,

E=mc^2

=0.046X0.75^2Xc^2

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The average period of pendulum clock is found to be 1.2s at sea level. The period of the same pendulum on a mountain top is foun
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Answer:

g' = 10.12m/s^2

Explanation:

In order to calculate the acceleration due to gravity at the top of the mountain, you first calculate the length of the pendulum, by using the information about the period at the sea level.

You use the following formula:

T=2\pi \sqrt{\frac{l}{g}}         (1)

l: length of the pendulum = ?

g: acceleration due to gravity at sea level = 9.79m/s^2

T: period of the pendulum at sea level = 1.2s

You solve for l in the equation (1):

l=\frac{gT^2}{4\pi^2}\\\\l=\frac{(9.79m/s^2)(1.2s)^2}{4\pi^2}=0.35m

Next, you use the information about the length of the pendulum and the period at the top of the mountain, to calculate the acceleration due to gravity in such a place:

T'=2\pi \sqrt{\frac{l}{g'}}\\\\g'=\frac{4\pi^2l}{T'^2}

g': acceleration due to gravity at the top of the mountain

T': new period of the pendulum

g'=\frac{4\pi^2(0.35m)}{(1.18s)^2}=10.12\frac{m}{s^2}

The acceleration due to gravity at the top of the mountain is 10.12m/s^2

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