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skad [1K]
3 years ago
9

A rock is thrown at an angle of 35.0° to the horizontal with a speed of 11.5 m/s. how far does it travel?​

Physics
1 answer:
coldgirl [10]3 years ago
8 0

Answer:

The distance covered by  the projectile is 12.68 m

Explanation:

Given;

angle of projection, θ = 35.0°

speed of projectile, v = 11.5 m/s

The distance covered by  the projectile is given by the range of the projection;

R = vt

R = \frac{v^2sin2\theta}{g} \\\\R = \frac{(11.5)^2 sin (2*35)}{9.8} \\\\R = 12.68 \ m

Therefore, the distance covered by  the projectile is 12.68 m.

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An eraser is thrown upward with an initial velocity of 5.0 m/s. The eraser's velocity after 7.0 seconds is ____ m/s.
Vedmedyk [2.9K]

Given parameters:

Initial velocity of eraser  = 5.0m/s

Time  = 7.0s

Unknown:

Final velocity = ?

Solution:

Since we have been given the initial velocity and duration of the throw, we can apply the appropriate motion equation to solve this problem.

       V  = U - 2gt

where V is the final velocity

            U is the initial velocity

             g is the acceleration due to gravity = 9.8m/s²

            t is the time taken

       V  = U - gt

       V = 5 - (9.8)(7)

       V = -63.6 or -64m/s

The velocity is -64m/s

   

3 0
3 years ago
A 72 kg skydiver is descending on a parachute. His speed is still increasing at 1.2 m/s2. What are the magnitude and direction o
frozen [14]

Answer:

86.4 N downward

Explanation:

Force: This can be defined as the product of mass and acceleration of a body.

The S.I unit of Force is Newton(N).

The Expression of force is given as,

F = ma ................ Equation 1

Where F = force of the parachute harness, m = mass of the skydiver, a = acceleration of the skydiver.

Given: m = 72 kg, a = 1.2 m/s²

Substitute into equation 1

F = 72(1.2)

F = 86.4 N down ward.

Hence the force on the parachute harness = 86.4 N downward

8 0
3 years ago
The three mountains task examines the development of
GalinKa [24]

Answer:

The Three Mountain Task was developed by Jean Piaget and Bärbel Inhelder in the 1940s to study children's ability to coordinate spatial perspectives. In the task, a child faced a display of three model mountains while a researcher placed a doll at different viewpoints of the display.

Explanation:

6 0
3 years ago
How can a small human retina detect objects larger than itself?
muminat

The correct answer would be A) the lenses of the eye change the size of images

5 0
3 years ago
A 26.0 g ball is fired horizontally with initial speed v0 toward a 110 g ball that is hanging motionless from a 1.10 m -long str
mart [117]

Answer:

7.3 ms^{-1}

Explanation:

Consider the motion of the ball attached to string.

In triangle ABD

Cos50 = \frac{AB}{AD} \\Cos50 = \frac{AB}{L}\\AB = L Cos50

height gained by the ball is given as

h = BC = AC - AD \\h = L - L Cos50\\h = 1.10 - 1.10 Cos50\\h = 0.393 m

M  = mass of the ball attached to string = 110 g

V = speed of the ball attached to string just after collision

Using conservation of energy

Potential energy gained = Kinetic energy lost

Mgh = (0.5) M V^{2} \\V = sqrt(2gh)\\V = sqrt(2(9.8)(0.393))\\V = 2.8 ms^{-1}

Consider the collision between the two balls

m  = mass of the ball fired = 26 g

v_{o} = initial velocity of ball fired before collision = ?

v_{f} = final velocity of ball fired after collision = ?

using conservation of momentum

m v_{o} = MV + m v_{f}\\26 v_{o} = (110)(2.8) + 26 v_{f}\\v_{f} = v_{o} - 11.85

Using conservation of kinetic energy

m v_{o}^{2} = MV^{2} + m v_{f}^{2} \\26 v_{o}^{2} = 110 (2.8)^{2} + 26 (v_{o} - 11.85)^{2} \\v_{o} = 7.3 ms^{-1}

3 0
3 years ago
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