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2 years ago

Concept of mole chemistry question

Chemistry

1 answer:

vredina [299]2 years ago

5 0

Answer:

How many molecules of water are there in 54 g of H2O H 2 O ? Solution. Molar Mass of H2O H 2 O = 2 + 16 = 18 g/moles. So ,number of moles of H2O H 2 O = Mass/Molar Mass = 54/18 =3 moles. Now 1 moles = 6.022×1023 6.022 × 10 23 molecule.

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Can anyone here help me with chemistry

Kay [80]

The answer is 20g N2

5 0

3 years ago

Someone help me Explain how non-genetic factors can affect phenotype. Give an example.

Yanka [14]

Answer:

one could be the weather.

phenotypes are physical characteristics of a person and there non genetic factors that play a role.

weather and environmental factors, your surroundings and orders related to the environment basically

6 0

3 years ago

Calculate δs∘rxn for the reaction2no(g) o2(g)→2no2(g)express your answer to one decimal place and include the appropriate units

Anna35 [415]

The δs∘rxn for the reaction $2NO(g) + O_{2}$ → $2NO_{2} (g)$ will be -146 J/K.

Entropy would be a measurable physical characteristic and a scientific notion that is frequently connected to a condition of disorder, unpredictability, or uncertainty.

Entropy would be a measurement of the system's unpredictability or disorder. The entropy increases as randomness do. It has broad properties as well as a state function. It has the unit $JK^{-1} mol^{-1}$ .

Entropy of the reaction can be calculated by the reaction.

Δ $S^{0} rxn$ = 2 mol × $S^{0} (NO_{2} (g) - 2 mol$ × $S^{0} NO (g)$ - 1 mol × $S^{0} (O_{2} )$

Δ $S^{0} rxn$ = 2 mol × 240 J/mol.K - 2 mol × 210 J/mol.K-1 mol ×205.2 J/mol.K

Δ $S^{0} rxn$ = -146.8 J/K

Therefore, the δs∘rxn for the reaction $2NO(g) + O_{2}$ → $2NO_{2} (g)$ will be -146 J/K.

To know more about reaction

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4 0

1 year ago

The liter is used to measure _____. weight mass volume length

Ket [755]

the answer to your question is

volume

4 0

3 years ago

Read 2 more answers

Suppose of potassium sulfate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of potassium

dimulka [17.4K]

Answer:

This question is incomplete, here's the complete question:

"Suppose 0.0842g of potassium sulfate is dissolved in 50.mL of a 52.0mM aqueous solution of sodium chromate. Calculate the final molarity of potassium cation in the solution. You can assume the volume of the solution doesn't change when the potassium sulfate is dissolved in it. Round your answer to 2 significant digits."

Explanation:

Reaction :-

K2SO4 + Na2CrO4 ------> K2CrO4 + Na2SO4

Mass of K2SO4 = 0.0842 g, Molar mass of K2SO4 = 174.26 g/mol

Number of moles of K2SO4 = 0.0842 g / 174.26 g/mol = 0.000483 mol

Concentration of Na2CrO4 = 52.0 mM = 52.0 * 10^-3 M = 0.052 mol/L

Volume of Na2CrO4 solution = 50.0 ml = 50 L / 1000 = 0.05 L

Number of moles of Na2CrO4 = 0.05 L * 0.052 mol/L = 0.0026 mol

Since number of moles of K2SO4 is smaller than number of moles Na2CrO4, so 0.000483 mol of K2SO4 will react with 0.000483 mol of Na2CrO4 will produce 0.000483 mol of K2CrO4.

0.000483 mol of K2CrO4 will dissociate into 2* 0.000483 mol of K^+

Final concentration of potassium cation

= (2*0.000483 mol) / 0.05 L = 0.02 mol/L = 0.02 M

8 0

3 years ago

Concept of mole chemistry question​

Concept of mole chemistry question