1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Oliga [24]
3 years ago
10

You are measuring the density of an irregularly shaped object. Using the analytical balance you determine the mass of your objec

t to be 38.88 grams. You then place the object into a graduated cylinder with 14.8mL of water, the volume rises to 33.4mL. Determine the density of your object tot he correct number of significant figures.
Chemistry
1 answer:
bija089 [108]3 years ago
4 0

Answer: 2.09g/mL

Explanation:

Mass = 38.88g

Volume of water = 14.8mL

Vol. of water + Vol. of object = 33.4mL

Vol. Of object = 33.4 — 14.8 = 18.6mL

Density = Mass / volume

Density = 38.88 / 18.6

Density = 2.09g/mL

You might be interested in
Using the periodic table, complete the table to describe each atom. Type in your answers.
katovenus [111]

Answer:

A<em>=</em><em>4</em>

<em>B</em><em>=</em><em> </em><em>4</em><em>+</em><em>2</em><em> </em><em>=</em><em>6</em>

<em>C</em><em>=</em><em>C</em><em>arbon</em>

<em>D</em><em>=</em><em>10</em>

<em>E</em><em>=</em><em>22</em>

<em>F</em><em>=</em><em>Argon</em><em> </em>

5 0
3 years ago
A solution of 20.0 g of which hydrated salt dissolved in
Dmitry_Shevchenko [17]

Answer:

(D) Na₂SO₄•10H₂O (M = 286).

Explanation:

  • The depression in freezing point of water by adding a solute is determined using the relation:

<em>ΔTf = i.Kf.m,</em>

Where, ΔTf is the depression in freezing point of water.

i is van't Hoff factor.

Kf is the molal depression constant.

m is the molality of the solute.

  • Since, Kf and m is constant for all the mentioned salts. So, the depression in freezing point depends strongly on the van't Hoff factor (i).
  • van't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.

(A) CuSO₄•5H₂O:

CuSO₄ is dissociated to Cu⁺² and SO₄²⁻.

So, i = dissociated ions/no. of particles = 2/1 = 2.

B) NiSO₄•6H₂O:

NiSO₄ is dissociated to Ni⁺² and SO₄²⁻.

So, i = dissociated ions/no. of particles = 2/1 = 2.

(C) MgSO₄•7H₂O:

MgSO₄ is dissociated to Mg⁺² and SO₄²⁻.

So, i = dissociated ions/no. of particles = 2/1 = 2.

(D) Na₂SO₄•10H₂O:

Na₂SO₄ is dissociated to 2 Na⁺ and SO₄²⁻.

So, i = dissociated ions/no. of particles = 3/1 = 3.

∴ The salt with the high (i) value is Na₂SO₄•10H₂O.

So, the highest ΔTf resulted by adding Na₂SO₄•10H₂O salt.

5 0
3 years ago
How many grams of sodium hydroxide, NaOH, are needed to make 355.0 mL of a 4.75M solution? The molar mass of NaOH is 40.00 g/mol
Katen [24]

Answer:

4198.97404999

Explanation:

In chemistry, the formula weight is a quantity computed by multiplying the atomic weight (in atomic mass units) of each element in a chemical formula by the number of atoms of that element present in the formula, then adding all of these products together.

Using the chemical formula of the compound and the periodic table of elements, we can add up the atomic weights and calculate molecular weight of the substance.

If the formula used in calculating molar mass is the molecular formula, the formula weight computed is the molecular weight. The percentage by weight of any atom or group of atoms in a compound can be computed by dividing the total weight of the atom (or group of atoms) in the formula by the formula weight and multiplying by 100.

8 0
2 years ago
The p subshell can hold up to eight electrons in an atom. True False
Reika [66]

Answer:

TRUE

Explanation:

Principal shell 2n has one s and one p subshell, and can hold a total of eight electrons. The p subshell has three dumbbell-shaped orbitals, as illustrated in Figure 4.

3 0
3 years ago
Read 2 more answers
Potassium sulfate has a solubility of 15g/100g water at 40 Celsius. A solution is prepared by adding 39.0g of potassium sulfate
nadya68 [22]

Answer:

5.25 grams of potassium sulfate will get crystallize out.

Explanation:

Solubility of potassium sulfate at 40 °C = 15 g/100 g

This means that at 40 °C 15 g of potassium sulfate will get completely dissolved in 100 of water.

39.0 g of potassium sulfate to 225 g water, carefully heating the solution.

Amount of potassium sulphate will get dissolve in 225 g of water at 40 °C will be:

\frac{15g}{100g} × 225 = 33.75g

Amount of potassium sulfate precipitated out by the solution:

= 39.0 g-33.75 g = 5.25 g

At 40 °C 5.25 g of potassium sulfate will get precipitate out from the solution which means that solution is saturated.

Saturated solution are solution in which solute is dissolved in maximum amount. Further addition of solute results in precipitation of solute form the solution.

5.25 grams of potassium sulfate will get crystallize out.

(Hope this Helps can I pls have brainlist (crown)☺️)

8 0
3 years ago
Other questions:
  • What would an effective conclusion need to include? In a scientific project.
    11·1 answer
  • Which of the following claims may be made based on your observations? (You will recieve negative points for wrong answers.)
    14·1 answer
  • Are compounds considered pure substances?
    8·1 answer
  • When I2 and FeCl2 are mixed together, iodine (I) cannot replace chlorine (Cl) in the compound because iodine is lower on the per
    7·1 answer
  • The molar mass of nitrogen (N2) is 28.02 g/mol. What is the mass, in grams, of 4.60 mol of N2?0.1646.0923.4129
    11·1 answer
  • Draw Lewis structures for each of the following moecules. Show resonance structures, if they exist
    13·1 answer
  • If 155 grams of potassium (K) reacts with 122 grams of potassium nitrate (KNO3), what is the limiting reagent? 2KNO3 + 10K 6K2O
    12·2 answers
  • What is the equation for determining gas pressure?
    5·2 answers
  • What are standard conditions when working with gases?
    14·1 answer
  • What is The compound with the formula SiCl4
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!