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Oliga [24]
3 years ago
10

You are measuring the density of an irregularly shaped object. Using the analytical balance you determine the mass of your objec

t to be 38.88 grams. You then place the object into a graduated cylinder with 14.8mL of water, the volume rises to 33.4mL. Determine the density of your object tot he correct number of significant figures.
Chemistry
1 answer:
bija089 [108]3 years ago
4 0

Answer: 2.09g/mL

Explanation:

Mass = 38.88g

Volume of water = 14.8mL

Vol. of water + Vol. of object = 33.4mL

Vol. Of object = 33.4 — 14.8 = 18.6mL

Density = Mass / volume

Density = 38.88 / 18.6

Density = 2.09g/mL

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Answer:

Explanation:

The pressure of a gaseous mixture is equal to the sum of the partial pressures of the individual gases:

ΣP_g_a_s = P_1+P_2+P_3+...+P_n

The prompt is trying to confuse you, but it actually tells us the pressure of the mixture to be 1 atm, but this can be converted to torr. Furthermore, we are informed only three gases are in the mixture: diatomic nitrogen, diatomic oxygen, and carbon dioxide:

P_g_a_s=1 \ atm = 760 \ torr= P_N_2+P_O_2+P_C_O_2\\760 \ torr = 582.008 \ torr + P_O_2 \ + 0.285 \ torr

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Thus, the partial pressure of diatomic oxygen is 177.707 torr.

<u><em>If you liked this solution, hit Thanks or give a Rating!</em></u>

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