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Nikolay [14]
3 years ago
5

Can some1 please answer these questions

Chemistry
1 answer:
Yakvenalex [24]3 years ago
4 0

Answer:

the answer of your question is yes

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Electrical energy is used to turn the blades of a fan. The amount of energy transformed is seen here: 750 J electrical energy is
Alchen [17]

B) It was transformed into 350 J of heat energy.

Explanation:

The remaining 350J of energy must have been transformed into 350J of heat energy.

A fan works by converting electrical energy into heat energy.

  • According to the third law of thermodynamics "no system is 100% efficient". The conversion of the energy from one form to another involves a lost in energy.
  • Heat is one very familiar way by which energy can be lost.
  • Some component energy is used to heat the fan in the process and it is a wasted energy.
  • Friction surfaces a heat energy in this process.

learn more:

Third law of thermodynamics brainly.com/question/3564634

#learnwithBrainly

6 0
4 years ago
How many moles of water as a gas can be formed 2.45 L
Alex17521 [72]

Answer:

0.11mole

Explanation:

Let us assume that the condition is at standard temperature and pressure(STP);

 Given parameters:

        Volume of water  = 2.45L

   Unknown:

       Number of moles found in this volume of water  = ?

Solution;

 At STP;

                 Number of moles  = \frac{volume of gas}{22.4}

 Input the parameters and solve;

                  Number of moles of water  = \frac{2.45}{22.4}   = 0.11mole

The number of moles of water found is  0.11mole

4 0
3 years ago
What is the electron configuration of aluminum?
Bond [772]
 <span>What is the electron configuration of aluminum is </span>1s^2 2s^2 2p^6 3s^2 3p^1.
8 0
3 years ago
What is the freezing point of a solution of 465 g of sucrose c12h22o11 dissolved in 575 ml of water?
Amanda [17]

Answer:

The freezing point of the solution is - 4.39 °C.

Explanation:

We can solve this problem using the relation:

<em>ΔTf = (Kf)(m),</em>

where, ΔTf is the depression in the freezing point.

Kf is the molal freezing point depression constant of water = -1.86 °C/m,

density of water = 1 g/mL.

<em>So, the mass of 575 mL is 575 g = 0.575 kg.</em>

m is the molality of the solution (m = moles of solute / kg of solvent = (465 g / 342.3 g/mol)/(0.575 kg) = 2.36 m.

<em>∴ ΔTf = (Kf)(m</em>) = (-1.86 °C/m)(2.36 m) = <em>- 4.39 °C.</em>

<em>∵ The freezing point if water is 0.0 °C and it is depressed by - 4.39 °C.</em>

<em>∴ The freezing point of the solution is - 4.39 °C.</em>

6 0
3 years ago
Name this compound Cr2(CO3)3
kiruha [24]

Answer:

Molecular Weight

Explanation:

Chromium(III) Carbonate Cr2(CO3)3 Molecular Weight -- EndMemo.

5 0
3 years ago
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