Answer:
15 3/4t^2 + 5 1/4
Explanation:
h(t)=-16t^2+400
We can add 400 then - 64 and show as 8^2
= h(t)=-16t^2+400 - 8^2
But we also need to change 16t^2;
We divide 64 into 16 = 16/64 =0.25
and show 16t^2 changes by 0.25 = 1/4
15 3/4t^2 + 400-64
Can now look like
15 3/4t^2 + 5 1/4
As 5 1/4 = 64 x 5 1/4 = 336
You must do work presented inside parentheses first. Thus, do this first: (-5-7).
Answer:
75 - 35y / 3 + 2y = -4
( 75 - 35y + 6y ) / 3 = -4 [ Taking LCM ]
( 75 - 29y ) / 3 = -4
75 - 29y = -12
29y = 75+12
29y = 87
y = 3
hope that helps ✌
Solving the given inequality for d, we get...
6d + 15 < 50
6d + 15-15 < 50-15 <<-- subtract 15 from both sides
6d < 35
6d/6 < 35/6 <<--- divide both sides by 6
d < 5.83
Which means that d can be any of the values in this set: {0, 1, 2, 3, 4, 5}
The smallest d can be is 0. In this scenario, Jeremy pays the $15 registration but doesn't rent the camera at all
The largest d can be is 5. In this scenario, Jeremy rents the camera for 5 days
Any larger value of d is not allowed as it would make the total cost go over $50
Notice how I'm rounding down regardless how close 5.83 is to 6
