Maybe he didn't want anyone seeing his weight? I'm not sure what the question is here.
Answer:
all real numbers except ±5.
Step-by-step explanation:
Each function (f(x), g(x)) has a domain that is all real numbers. Their quotient (f(x)/g(x)) must exclude values that make g(x) = 0. The quotient is undefined when the denominator is zero. Those excluded values are x = ±5.
The domain of (f/g)(x) is all real numbers except ±5.
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Of course you recognize x^2 -25 = 0 has solutions x = ±√25 = ±5. You can get there two ways:
- add 25 and take the square root: x^2=25; x=±√25.
- factor the difference of squares and set the factors to zero: (x-5)(x+5)=0 has solutions x-5=0 and x+5=0, that is, x = ±5.
Answer:
I think 5 because they both go into it
The second and last one.
The second one multiplies the cost of each type of ticket by two, therefore saying that you wanted to buy two of each type of ticket.
The last one multiplies the cost of a single ticket of all three types and multiplies it by 2.
Can you take a closer pic of this
