Complete Question 
A 95 kg clock initially at rest on a horizontal floor requires a 650 N horizontal force to set it in motion. After the clock is in motion, a horizontal force of 560 N keeps it moving with a constant velocity. Find the coefficient of static friction and the coefficient of kinetic friction.
Answer:
The value for static friction is 
The value for static friction is 
Explanation:
From the question we are told that 
 The mass of the clock is 
 The first horizontal force is 
     The second horizontal force is    
Generally the static frictional force is equal to the first  horizontal force 
 So 
      
=>   
=>    
Generally the kinetic frictional force is equal to the second horizontal force 
 So
       
       
      