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Monica [59]
3 years ago
8

In the following circuit, the supplied voltage is 1.5 volts and the resistor value is 2 ohms. Use Ohm's law to determine the cur

rent in the circuit.
3.0 amps
0.75 amps
3.5 amps
1.3 amps
Physics
2 answers:
attashe74 [19]3 years ago
7 0

Answer:

0.75 Amps

Explanation:

I had this question and this was right

RSB [31]3 years ago
5 0

Answer:

Current, I = 0.75 amps

Explanation:

Given that

Supplied voltage, V = 1.5 volts

Value of resistor, R = 2 ohms

Ohm's law to used to determine the current in the circuit. Mathematically, it is given by :

V = I R

I = current flowing in the circuit

I=\dfrac{V}{R}

I=\dfrac{1.5\ V}{2\ ohms}

I = 0.75 amps

So, the current flowing in the circuit is 0.75 amps. Hence, the correct option is (b) ''0.75 amps''.

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if two point charges are separated by 1.5 cm and have charge values of 2.0 and -4.0, respectively, what is the value of the mutu
RUDIKE [14]

Complete question:

if two point charges are separated by 1.5 cm and have charge values of +2.0 and -4.0 μC, respectively, what is the value of the mutual force between them.

Answer:

The mutual force between the two point charges is 319.64 N

Explanation:

Given;

distance between the two point charges, r = 1.5 cm = 1.5 x 10⁻² m

value of the charges, q₁ and q₂ = 2 μC and - μ4 C

Apply Coulomb's law;

F = \frac{k|q_1||q_2|}{r^2}

where;

F is the force of attraction between the two charges

|q₁| and |q₂| are the magnitude of the two charges

r is the distance between the two charges

k is Coulomb's constant = 8.99 x 10⁹ Nm²/C²

F = \frac{k|q_1||q_2|}{r^2} \\\\F = \frac{8.99*10^9 *4*10^{-6}*2*10^{-6}}{(1.5*10^{-2})^2} \\\\F = 319.64 \ N

Therefore, the mutual force between the two point charges is 319.64 N

4 0
3 years ago
A ship leaves a harbor and sails at 23.5 ∘ to the north of due west. After traveling 575 km, how far west is the ship from the h
solniwko [45]

Answer:

D = 527.31 Km

Explanation:

given,

angle of ship, θ = 23.5° N of W

distance travel in the direction = 575 Km

Distance of ship in west from harbor = ?

now,

Distance of the ship in the west direction

D = d cos θ

d = 575 Km

θ = 23.5°

inserting all the values

D = 575 x cos 23.5°

D = 575 x 0.91706

D = 527.31 Km

Hence, the distance travel by the ship in west from harbor is equal to D = 527.31 Km  

6 0
3 years ago
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Answer:

u need to make sure that comparison is = to shapes and then find the shapes sizes and add them

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A model airplane with mass 1.3 kg hangs from a rubber band with spring
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Answer:

<u>0.64 m </u>

Explanation:

Just done a while ago.

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Everything is perished.........(is it,isn't it, aren't they, are they​
andrey2020 [161]

Answer:

everything is perished isn't it?

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