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Monica [59]
4 years ago
8

In the following circuit, the supplied voltage is 1.5 volts and the resistor value is 2 ohms. Use Ohm's law to determine the cur

rent in the circuit.
3.0 amps
0.75 amps
3.5 amps
1.3 amps
Physics
2 answers:
attashe74 [19]4 years ago
7 0

Answer:

0.75 Amps

Explanation:

I had this question and this was right

RSB [31]4 years ago
5 0

Answer:

Current, I = 0.75 amps

Explanation:

Given that

Supplied voltage, V = 1.5 volts

Value of resistor, R = 2 ohms

Ohm's law to used to determine the current in the circuit. Mathematically, it is given by :

V = I R

I = current flowing in the circuit

I=\dfrac{V}{R}

I=\dfrac{1.5\ V}{2\ ohms}

I = 0.75 amps

So, the current flowing in the circuit is 0.75 amps. Hence, the correct option is (b) ''0.75 amps''.

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Answer:

A)

Explanation:

Energy transformation is when energy changes from one form to another.

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Red light of wavelength 633 nmnm from a helium-neon laser passes through a slit 0.360 mmmm wide. The diffraction pattern is obse
777dan777 [17]

Answer:

      Δy= 5,075 10⁻⁶ m

Explanation:

The expression that describes the interference phenomenon is

      d sin θ = (m + ½) λ

As the observation is on a distant screen

     tan θ = y / x

     tan θ= sin θ/cos θ

As in ethanes I will experience the separation of the vines is small and the distance to the big screen

          tan θ = sin θ

Let's replace

     d y / x = (m + ½) λ

The width of a bright stripe at the difference in distance  

     y₁ = (m + ½) λ x / d

     m = 1

      y₁ = 3/2 λ x / d

Let's use m = 1, we look for the following interference,

             m = 2

             y₂ = (2+ ½) λ x / d

The distance to the screen is constant x₁ = x₂ = x₀

The width of the bright stripe is

           Δy = λ x / d (5/2 -3/2)

           Δy = 630 10⁻⁹ 2.90 /0.360 10⁻³ (1)

           Δy= 5,075 10⁻⁶ m

8 0
3 years ago
Suppose you average 75 MPH over the first halfof a drive, and your average speed for the entiredrive is 60 MPH. What was your av
alexandr402 [8]

Answer:

x = 45 MPH

Explanation:

given,

Average speed of the first half = 75 MPH

Average speed of entire ride = 60 MPH

Average speed of the second half = ?

let the average speed of the second half = x MPH

now,

average of entire ride is given as 60 mph so,

 \dfrac{75+x}{2} = 60

 75+x= 2\times 60

       75 + x = 120

         x = 120 -75

        x = 45 MPH

hence, the average speed of the second half comes out to be 45 MPH.

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4 years ago
In the final situation below, the 8.0 kg box has been launched with a speed of 10.0 m/s across a frictionless surface. Find the
Murljashka [212]

Answer:

the energy of the spring at the start is 400 J.

Explanation:

Given;

mass of the box, m = 8.0 kg

final speed of the box, v = 10 m/s

Apply the principle of conservation of energy to determine the energy of the spring at the start;

Final Kinetic energy of the box = initial elastic potential energy of the spring

K.E = Ux

¹/₂mv² = Ux

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400 J = Ux

Therefore, the energy of the spring at the start is 400 J.

8 0
3 years ago
At t= 0, a particle moving in the xy plane with constant acceleration has a velocity of Vi= (3.00i -2.00j) m/s and is at the ori
ivanzaharov [21]

Answer:

(a) a = (2i + 4.5j) m/s^2

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Explanation:

(a) The acceleration of the particle is given by:

\vec{a}=\frac{\vec{v}-\vec{v_o}}{t}\\\\

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t = 3s

by replacing the values of the vectors and time you obtain:

\vec{a}=\frac{1}{3s}[(9.00-3.00)\hat{i}+(7.00-(-2.00))\hat{j}]\\\\\vec{a}=(2\hat{i}+4.5\hat{j})m/s^2

(b) The position vector is given by:

\vec{r}=\vec{r_o}+\vec{v_o}t+\frac{1}{2}\vec{a}t^2

where vo = (3.00i -2.00j) m/s and a = (2.00i + 4.50j)m/s^2

4 0
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