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iVinArrow [24]
4 years ago
14

El muelle de un dinamómetro se alarga 6cm cuando aplicamos sobre él una fuerza de 10 N. Calcula el alargamiento del muelle al ap

licar una fuerza de 20 N.
Physics
1 answer:
Crank4 years ago
6 0

Answer:

x = 12cm

Explanation:

First, with the values given for the force and the displacement, you calculate the spring-constant of the dynamometer by using the following equation (primero, con los valores dados de la fuerza y el desplazamiento, calculas la constante del resorte aplicando la siguiente formula):

F=kx

F: force (fuerza) = 10N

k: spring constant (constante del resorte)

x: displacement of the spring (desplazamiento del resorte) = 6cm

by using these values you calculate k (usando estos valores calculas k):

k=\frac{F}{x}=\frac{10N}{6cm}=1.66\frac{N}{cm}

With this value you calculate the displacement for a force of 20N (con este valor de k calculas el desplazamiento del resorte para una fuerza de 20N):

x=\frac{F}{k}=\frac{20}{1.66N/cm}=12cm

hence, the displacement is 12cm

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Answer:

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Explanation:

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3 years ago
Scientists believe that Earth and the other planets formed _____.
Gnoma [55]
C. during the same time span and from the same material as the sun
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A 13 kg hanging sculpture is suspended by a 95-cm-long, 5.0 g steel wire. When the wind blows hard, the wire hums at its fundame
Artyom0805 [142]

Answer:

f=81.96 \ Hz

Explanation:

Givens

L=95cm

m_{sculpture} =13kg

m_{wire}=5g

The frequency is defined by

f=\frac{v}{\lambda}

Where v is the speed of the wave in the string and \lambda is its wave length.

The wave length is defined as \lambda = 2L = 2(0.95m)=1.9m

Now, to find the speed, we need the tension of the wire and its linear mass density

v=\sqrt{\frac{T}{\mu} }

Where \mu=\frac{0.005kg}{0.95m}= 5.26 \times 10^{-3} and the tension is defined as T=m_{sculpture} g=13kg(9.81 m/s^{2} )=127.53N

Replacing this value, the speed is

v=\sqrt{\frac{127.53N}{5.26 \times 10^{-3} } }=155.71 m/s

Then, we replace the speed and the wave length in the first equation

f=\frac{v}{\lambda}\\f=\frac{155.71 m/s}{1.9m}\\ f=81.96Hz

Therefore, the frequency is f=81.96 \ Hz

3 0
3 years ago
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Frank has a sample of steel that has a mass of 80 grams if the density is 8g/cm3 what is the volume
nikklg [1K]
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A hot air balloon is hovering in the air when it drops a 40 Kg food package to some lost golfers. If the package is dropped from
UNO [17]
We can calculate this with the law of conservation of energy. Here we have a food package with a mass m=40 kg, that is in the height h=500 m and all of it's energy is potential. When it is dropped, it's potential energy gets converted into kinetic energy. So we can say that its kinetic and potential energy are equal, because we are neglecting air resistance:

Ek=Ep, where Ek=(1/2)*m*v² and Ep=m*g*h, where m is the mass of the body, g=9.81 m/s² and h is the height of the body.

(1/2)*m*v²=m*g*h, masses cancel out and we get:

(1/2)*v²=g*h, and we multiply by 2 both sides of the equation

v²=2*g*h, and we take the square root to get v:

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v=99.04 m/s

So the package is moving with the speed of v= 99.04 m/s when it hits the ground. 
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