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3 years ago

Which law states that absolute zero cannot be reached?

2 answers:

5 0

The third law of thermodynamics,the principle of temperature.

This law states that the entropy at 0 is always equel to 0.
This means that it is impossible to cool down a perfect 0 or absolute 0(-273.15 C)

nalin [4]3 years ago

4 0

The answer is third law

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Suppose that a parallel-plate capacitor has circular plates with radius R = 26 mm and a plate separation of 4.0 mm. Suppose also

Paraphin [41]

Answer:

B(max) = 3.7971 × $10^{-12}$ T

Explanation:

given data

radius R = 26 mm

plate separation d = 4.0 mm

potential difference Vm = 220 V

frequency f = 76 Hz

V = (220 V) sin[2π(76 Hz)t]

solution

we know that E will be

E = V ÷ d ............1

put here value

E = $\frac{220 \times sin(2\pi 76\times t)}{d}$

and here we take as given r = R

so A = π R² .................2

and

ФE = E × A

ФE = $\frac{\pi R^2 \times 220 \times sin(2\pi 76 \times t)}{d}$ .....................3

so use use here now Ampere's Law that is

∫ B ds = $\mu_o \times \epsilon_o \times \frac{d\Phi E}{dt} + \mu_o \times I_{encl}$ .....................4

and

here $I_{encl}$ is = 0 and r = R

$2B \times \pi \times R = \mu_o \times \epsilon_o \times \frac{d\Phi E}{dt}$ .....................5

and put here value we get

B = $\frac{\mu_o \times \epsilon_o \times \pi \times f \times R \times V_m cos(2\pi f t)}{d}$ .....................6

put here value for B maximum cos(2πft) = 1

and we get B (max)

B(max) = $\frac{\mu_o\times \epsilon_o\times \pi \times f\times R\times V_m}{d}$ ....................7

put here all value

B(max) = $\frac{4\pi \times10^{-7} \times 8.85\times 10^{-12}\times \pi \times 76 \times 0.026\times 220 }{4\times 10^{-3}}$

solve it we get

B(max) = 3.7971 × $10^{-12}$ T

5 0

4 years ago

A student hooks up a voltmeter and an ammeter in a circuit to find the resistance of a light bulb. The ammeter read 3 amps and t

yuradex [85]

Answer:

$2\Omega$

Explanation:

(Assuming the cell in the circuit has 0 internal resistance)

Ohm's Law is given as:

$V=IR$

Voltage is Current multiplied by Resistance.

We can rearrange this formula to give us:

$R=\frac{V}{I}$

Now we can plug in our values

$R=\frac{6}{3}=2\Omega$

7 0

3 years ago

Read 2 more answers

A small piece of aluminum (atomic number 13) contains 10^15 atoms (The atomic number is the number of protons; it determines the

Otrada [13]

Answer:

3 micro coulombs = 3 * 10E-6 coulombs charge of aluminum

13 * 10E15 * 1.6 * 10E-19 = 2.08 E-3 Coulombs - charge of atoms in Al

3 * 10E-6 / 2.08 * E-3 = 1.44 * E-3 = .00144 = .144 %

.00144 of the original electrons would have to be lost

8 0

3 years ago

Why does New and Full moons produce stronger tides.

serious [3.7K]

Because at the time of New and Full moons, the Earth, Sun,
and Moon are all lined up on the same line. So the effects
of the Sun and Moon combine to influence the tides in the
same direction.

4 0

4 years ago

A ray of monochromatic light ( f = 5.09 × 10^14 Hz) passes from air into Lucite at an angle

harina [27]

Let us consider the air with the index 1 and the lucite with index 2. Using the Snell's Secound Law, we have:

$\frac{sen\O_{2}}{sen\O_{1}} = \frac{n_{2}}{n_{1}} \\ sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}}$

Entering the unknowns, remembering that the air refrective index is 1 and the lucite refrective index is 1.5, comes:

$sen\O_{2}= \frac{n_{2}*sen\O_{1}}{n_{1}} \\ sen\O_{2}= \frac{1.5* \frac{1}{2} }{1} \\ sen\O_{2}=0.75$

Using the arcsin properties, we get:

$sen\O_{2}=0.75 \\ arcsin(0.75)=\O_{2} \\ \boxed {\O_{2}=48.59^o}$

Obs: Approximate results, and the drawing is attached

If you notice any mistake in my english, let me know, because i am not native.

6 0

3 years ago