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2 years ago

Eva has four sets of straws.

Mathematics

2 answers:

hodyreva [135]2 years ago

8 0

D

You need to use trigonometry, and square all of the numbers, you then add the lowest two and they should sum to the other number.

The set that this works for is the correct set.

Hope this helps x

Tasya [4]2 years ago

5 0

Set D, Pythagorean theory
Side 1 sq + side 2 sq = side 3 sq
5sq + 12sq = 13sq
25 + 144 = 169

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Please provide the answer?

Brums [2.3K]

Using the given table:

a) the average rate of change is 32.5 jobs/year.

b) the average rate of change is 12.5 jobs/year.

<h3>How to find the average rate of change?</h3>

For a function f(x), the average rate of change on an interval [a, b] is:

$\frac{f(b) - f(a)}{b - a}$

a) The average rate of change between 1997 and 1999 is:

$A = \frac{695 - 630}{1999 - 1997} = 32.5$

So the average rate of change is 32.5 jobs/year.

b) Now the interval is 1999 to 2001.

The rate this time is:

$A ' = \frac{720 - 695}{2001 - 1999} = 12.5$

So the average rate of change is 12.5 jobs/year.

If you want to learn more about average rates of change:

brainly.com/question/8728504

#SPJ1

3 0

1 year ago

Kevin hiked up lambs Canyon and two hours and then ran back down in one hour has been running downhill was 2.8 mph greater than

coldgirl [10]

Answer: he hiked 5.6 miles up the canyon.

Step-by-step explanation:

Let x represent his speed hiking uphill.

His speed running downhill was 2.8 mph greater than his speed hiking uphill. This means that his speed running downhill would be x + 2.8

Distance = speed × time

Kevin hiked up Lamb’s Canyon in 2 hours. This means that the distance covered by hiking uphill is 2 × x = 2x

He ran back downhill in 1 hour. This means that the distance covered by running downhill is 1 × (x + 2.8) =

x + 2.8

Since the distance uphill is the same as the distance downhill, then

2x = x + 2.8

2x - x = 2.8

x = 2.8

Therefore, the distance hiked up the canyon is

2x = 2 × 2.8 = 5.6 miles

8 0

3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago

4.<br> Which equation in point-slope form contains the point (-3, 5) and has slope -1?<br> 100%

Flura [38]

ʕ•ﻌ•ʔ $\huge\bold\pink{hello!!!}$ ʕ•ﻌ•ʔ

HERE IS UR ANSWER

_____________________

(x-(-3)) = -1(y-5)

(x+3)= -y+5

x+y+3-5=0

x+y-2=0

3 0

2 years ago

This maximization linear programming problem is not in "standard" form. It has mixed constraints, some involving ≤ inequalities

stellarik [79]

Answer: See Annex

z (max) = 190

x = 10

y = 20

Step-by-step explanation:

z = 5*x + 7*y to maximize

Subject to:

x + y ≤ 30

2*x + y ≤50

2*x - y ≥ 0

x≥= y ≥0

5 0

3 years ago